I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer:
see below
Step-by-step explanation:
x - c > dy
x > dy + c
Your answer in scientific notation is 2.355 * 10^14
You're just going to take exponents of 4. For example, 4 to the power of 1, 4 to the power of 2, 4 to the power of 3, and so on. To get the powers of 4, just multiply 4 by how much the exponent reads. For example 4 to the power of 3 is just 4 multiplied by itself 3 times.
4^1=4
4^2=16
4^3=64
4^4=256
4^5=1024
However, 1024 is greater than 1000 so we do not include it.
