Jerry had a 3 in 10 chance or a 30 percent chance to hit area A randomly
Answer:
|−93| = −93
Step-by-step explanation:
|Mode| = mode
h(x) = 5 - 9x
h(8) = 5 - 9×8 ( putting value x = 8)
h(8) = 5 - 72
h(8) = -67
Answer is -67.
Answer:
a) -1.25
b) 0.2112
c) -1.96
Step-by-step explanation:
Data provided in the question:
Sample size, n = 400
H0 : p = 20
= 175
Now,
a) The test statistic is given as:
Z = 
on substituting the respective values, we get
Z = 
= -1.25
b) The p-value = 2 × P(Z <-1.25)
Now from the standard normal table
P(Z <-1.25) = 10.56% = 0.1056
Thus,
p-value = 2 × 1056 = 0.2112
c) for a = 0.05,
the critical value is
i.e 
Now from standard normal table
= -1.96
Answer: C should be correct!
Hope it helps!