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Jlenok [28]
3 years ago
10

How much will it cost to pour a circular slab 18 ft in diameter by 3 in. For a patio if the concrete costs $40.00 per cubic yard

? (1 cubic yard = 27 cubic feet)
Mathematics
1 answer:
valkas [14]3 years ago
7 0

Answer:

$94.24

Step-by-step explanation:

Given :

Diameter of circular slab = 18feet

Thickness of slab = 3 inches ; inches to ft = 3 /12 = 0.25 feets

Volume of slab = πd²t/4 = (π*18²*0.25) / 4 = 63.6 ft³

1 cubic yard = 27 feet

Volume in yard = 63.6 / 27 = 2.356 yd³

Concrete = $40 per yd³

Cost = $40 * 2.356 = $94.24

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The population of Hicksville increased from 20,000 to 24,500 in the past decade. What is the percent of increase in population o
Leona [35]
40 percent???





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Which statement is true?
diamong [38]

3 is correct , base is never equal to 1 cause all of solves of logarithm will be 0

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Read 2 more answers
What are the possible values of x in 8x2 + 4x = -1?
Westkost [7]

Answer:

The possible values of x are:

x= \frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18

and

x= \frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68

Step-by-step explanation:

8x^2+4x+1=0

Using Quadratic formula to solve this equation:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a = 8 \,\, b = 4\,\, c = -1\\Putting \,\, values \,\, in \,\, the\,\, equation\\x= \frac{-4\pm\sqrt{(4)^2-4(8)(-1)}}{2(8)}\\x= \frac{-4\pm\sqrt{16+32}}{16}\\x= \frac{-4\pm\sqrt{48}}{16}\\x= \frac{-4+ \sqrt{48}}{16} \,\, and \,\, x= \frac{-4- \sqrt{48}}{16}\\x= \frac{-1+ \sqrt{3}}{4} \,\, and \,\, x= \frac{-1- \sqrt{3}}{4}

The possible values of x are:

x= \frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18

and

x= \frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68

4 0
3 years ago
An oil tank is leaking into a lake at a rate of 0.1 m3/day. The oil slick forms a semicircular disk whose center is at the leak
gregori [183]

Answer:

17.9  m/s

Step-by-step explanation:

Volume of the slick =  0.5 x π r² h--------------------------------- (1)

Where r = radius of slick

           h = thickness of slick, 10⁻⁶m

If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)

V  =  0.5 x π r² h

0.5=  0.5 x  π x  r² x 10⁻⁶

r²   =  10⁶/ π

r =     10³/√π

dV/dt =   πrh dr/dt  + 0.5π r² dh/dt----------------------------------- (2)

Asumming the film thickness is constant , equation (2) becomes

dV/dt =   πrh dr/dt-------------------------------- (3)

dV/dt = 0.1m³/day

r=  10³/√π

dr/dt= rate of expansion of the slick

Substituting  into (3);

0.1 =  π x 10³/√π x 10⁻⁶ x dr/dt

dr/dt = 0.1  x 10⁶/ ( π x 10³/√π)

       =  17.9479 m/s

       ≅  17.9  m/s

8 0
4 years ago
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