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Harlamova29_29 [7]
4 years ago
5

Expand the given power by using Pascal’s triangle. (9a - 10b)^6

Mathematics
1 answer:
xxMikexx [17]4 years ago
8 0

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

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Identify the equivalent expression for each of the expressions below.<br> (m^1/3)^1/5
GREYUIT [131]

Answer:

(m^{\frac{1}{3} })^{\frac{1}{5} }= m^{\frac{1}{15} \\\\

4 0
3 years ago
The city of Oakland is experiencing a movement of its population to the suburbs. At present 85% of the total population lives in
Oxana [17]

Answer:

A. \left[\begin{array}{cc}0.93&0.07&\\0.01&0.99&\end{array}\right]

B.   (0.85    0.15)

C. 79.2% population in the city while 20.8% population in the suburb

Step-by-step explanation:

(a) The transition matrix for the information is

                C        S

            \left[\begin{array}{cc}0.93&0.07&\\0.01&0.99&\end{array}\right]

(b) the probability vector for the information is

         (\frac{85}{100}  \ \   \frac{15}{100} )

and this gives us

         (0.85    0.15)

(c) we simply multiply the above  two matrices to find the percent of the population can be expected to be in each category after one year after

\left[\begin{array}{cc}0.85&0.15\end{array}\right] \left[\begin{array}{cc}0.93&0.07&\\0.01&0.99&\end{array}\right] = \left[\begin{array}{cc}0.792&0.208&\end{array}\right]

in the city there are 79.2% while in the suburb, there are 20.8%

5 0
3 years ago
What is the solution set to the equation (3x−9)(5x−3)=0?
andreev551 [17]
This product could be zero if one or both of the parenthesis are zero.
3x-9=0; 3x=9; x= 3
5x-3=0; 5x=3; x=3/5

The solution is { 3/5, 3}
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3 years ago
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8 0
4 years ago
Read 2 more answers
4) Use the Euclidean algorithm to find the greatest common divisor d of 313,626 and 152,346. Then use this algorithm to find int
Kryger [21]

Answer:

Greatest common divisor of 313,626 and 152,346 is 6

s = -3581 and t = 7373

Step-by-step explanation:

  1. gcd(313626, 152346) = gcd(152346, 8934)   since 313626 = (2 × 152346) + 8934
  2. gcd(152346, 8934) = gcd(8934, 468)   since 152346 = (17 × 8934) + 468
  3. gcd(8934, 468)  = gcd(468, 42)            since 8934 = (19 × 468) + 42
  4. gcd(468, 42)  = gcd(42, 6)                     since 468 = (11 × 42) + 6
  5. gcd(42, 6) = gcd(6, 0)                            since 42 = 7 × 6 + 0
  6. gcd(6, 0)  = 6

Working backwards from the third-to-last line,

6 = 468 - (11 × 42)      (line 4)

42 = 8934 - (19 × 468)         (line 3)

Substituting this for 42 in the previous,

6 = 468 - 11(8934 - (19 × 468))

6 = (210 × 468) - (11 × 8934)

Still working backwards,

468 = 152346 - 17 × 8934      (line 2)

Substituting this for 468 in the previous,

6 = (210 × (152346 - 17 × 8934)) - (11 × 8934)

6 = (210 × 152346) - (8934 × 3581)

On line 1,

8934 = 313626 - 2 × 152346

Substituting this for 8934 in the previous,

6 = (210 × 152346) - ((313626 - 2 × 152346) × 3581)

6 = (7372 × 152346) - (313626 × 3581)

Hence, s = -3581 and t = 7373

5 0
3 years ago
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