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3 years ago

What is the solution set to the equation (3x−9)(5x−3)=0?

2 answers:

8 0

This product could be zero if one or both of the parenthesis are zero.
3x-9=0; 3x=9; x= 3
5x-3=0; 5x=3; x=3/5

The solution is { 3/5, 3}

almond37 [142]3 years ago

6 0

Answer:

({3,\frac{3}{5} })

Step-by-step explanation:

Given is an equation in x with two factors on left side and 0 on right side as

$(3x−9)(5x−3)=0$

We know that when product of two factors is zero, then any one of the factors can be 0

Equate each factor to 0

$(3x−9)=0\\(5x−3)=0\\x=3\\x=\frac{3}{5}$

Thus we have two solutions

x=3\\

x=\frac{3}{5}

Solution set is

$({3,\frac{3}{5} })$

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Step-by-step explanation:

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3 years ago

(pages 2-7)

user100 [1]

Answer:

The answer is here

Step-by-step explanation:

https://www.khanacademy.org/test-prep/praxis-math/praxis-math-lessons/gtp--praxis-math--lessons--geometry/a/gtp--praxis-math--article--congruence-and-similarity--lesson

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3 years ago

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erastovalidia [21]

Answer:

Option b) $\frac{17}{260}$

Step-by-step explanation:

We are given the following information in the question:

Total number of marbles = 65

Number of green marbles = 17

We have to find the probability of drawing 2 green marbles at random without replacement.

Formula:

$Probability = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

$\text{P(Drawing 2 green marbles at random without replacement)} = \\\text{Probability of drawing }1^{st} \text{ green marble}\times \text{Probability of drawing }2^{nd} \text{ green marble}$

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$\text{P(Drawing 2 green marbles at random without replacement)} =\displaystyle\frac{17}{65}\times \frac{16}{64}=\frac{17}{260}$

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