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madreJ [45]
3 years ago
12

What is the solution set to the equation (3x−9)(5x−3)=0?

Mathematics
2 answers:
andreev551 [17]3 years ago
8 0
This product could be zero if one or both of the parenthesis are zero.
3x-9=0; 3x=9; x= 3
5x-3=0; 5x=3; x=3/5

The solution is { 3/5, 3}
almond37 [142]3 years ago
6 0

Answer:

({3,\frac{3}{5} })

Step-by-step explanation:

Given is an equation in x with two factors on left side and 0 on right side as

(3x−9)(5x−3)=0

We know that when product of two factors is zero, then any one of the factors can be 0

Equate each factor to 0

(3x−9)=0\\(5x−3)=0\\x=3\\x=\frac{3}{5}

Thus we have two solutions

x=3\\

x=\frac{3}{5}

Solution set is

({3,\frac{3}{5} })

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**WILL MARK BRAINLIEST** PLEASE ANSWER!! please ??
geniusboy [140]

Answer:

Port eagle has the higher median

Step-by-step explanation:

That's all I will give you.

Why?

Because the median is the average which would be the middle range between two points.

7 0
3 years ago
Find the midpoint of a segment whose endpoints are (9, –7) and (–3, 5).
suter [353]
For this question, you would have to use the midpoint formula. 
(X1 +X2 / 2 , Y1 + Y2 / 2)

In other words, 
(9 + -3 / 2 , -7 +5 / 2)
(6 / 2 , -2 / 2)
(3 , -1)

Your midpoint is (3, -1)
7 0
3 years ago
1 2 3 4 5 6 7 8 9 10
daser333 [38]
<h3>Answer:</h3>

2.25

<h3>Explanation:</h3>

Consider the square ...

... (x+a)² = x² +2ax +a²

The constant term (a²) is the square of half the x-coefficient: a² = (2a/2)².

The x-coefficient in your expression is 3. The square of half that is ...

... (3/2)² = 9/4 = 2.25

Adding 2.25 to both sides gives ...

... x² +3x + 2.25 = 6 + 2.25

... (x +1.5)² = 8.25 . . . . completed square

4 0
3 years ago
Cassidy's diving platform is 6 ft above the water. One of her dives can
avanturin [10]

Answer:

Before coming back up to the surface the maximum depth, Cassidy went was 6.25 ft. below the water surface

Step-by-step explanation:

The height of Cassidy's diving platform above the water = 6 ft.

The equation that models her dive is d = x² - 7·x + 6

Where;

d = Her vertical position or distance from the water surface

x = Here horizontal distance from the platform

At Cassidy's maximum depth, we have;

dd/dx = d(x² - 7·x + 6)/dx = 2·x - 7 = 0

x = 7/2 = 3.5

∴ At Cassidy's maximum depth, x = 3.5 ft.

The maximum depth, d_{max} = d(3.5) = 3.5² - 7 × 3.5 + 6 = -6.25

The maximum depth, Cassidy went before coming back up to the surface = d_{max} = -6.25 ft = 6.25 ft. below the surface of the water.

8 0
2 years ago
Find the volume of the solid.
dmitriy555 [2]

In Cartesian coordinates, the region (call it R) is the set

R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}

In the plane z=2, we have

2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2

which is a circle with radius \sqrt2. Then we can better describe the solid by

R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}

so that the volume is

\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx

While doable, it's easier to compute the volume in cylindrical coordinates.

\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}

Then we can describe R in cylindrical coordinates by

R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}

so that the volume is

\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}

3 0
1 year ago
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