Answer:
.
Step-by-step explanation:
We have been given that
and
. We are asked to write N as a discrete exponential function of t of the form
.
Using our given information, we can set an equation as:
![N(0)=A(1+r)^0](https://tex.z-dn.net/?f=N%280%29%3DA%281%2Br%29%5E0)
![84=A*1](https://tex.z-dn.net/?f=84%3DA%2A1)
![84=A](https://tex.z-dn.net/?f=84%3DA)
Using our given information, we will get:
![N(11)=A(1+r)^{11}](https://tex.z-dn.net/?f=N%2811%29%3DA%281%2Br%29%5E%7B11%7D)
Substitute the given values:
![130=84(1+r)^{11}](https://tex.z-dn.net/?f=130%3D84%281%2Br%29%5E%7B11%7D)
![\frac{130}{84}=\frac{84(1+r)^{11}}{84}](https://tex.z-dn.net/?f=%5Cfrac%7B130%7D%7B84%7D%3D%5Cfrac%7B84%281%2Br%29%5E%7B11%7D%7D%7B84%7D)
![1.5476190476190476=(1+r)^{11}](https://tex.z-dn.net/?f=1.5476190476190476%3D%281%2Br%29%5E%7B11%7D)
Switch sides:
![(1+r)^{11}=1.5476190476190476](https://tex.z-dn.net/?f=%281%2Br%29%5E%7B11%7D%3D1.5476190476190476)
Take 11th root of both sides:
![\sqrt[11]{(1+r)^{11}}=\sqrt[11]{1.5476190476190476}](https://tex.z-dn.net/?f=%5Csqrt%5B11%5D%7B%281%2Br%29%5E%7B11%7D%7D%3D%5Csqrt%5B11%5D%7B1.5476190476190476%7D)
![1+r=1.04050024747304](https://tex.z-dn.net/?f=1%2Br%3D1.04050024747304)
![r=1.04050024747304-1](https://tex.z-dn.net/?f=r%3D1.04050024747304-1)
![r=0.04050024747304](https://tex.z-dn.net/?f=r%3D0.04050024747304)
![r\approx 0.0405](https://tex.z-dn.net/?f=r%5Capprox%200.0405)
Therefore, our required function would be
.
Answer:
a= 30
b=60
c=105
Step-by-step explanation:
A forms a vertical angle with another angle that measures 30 degrees, therefore,
a= 30 degrees.
Since a is 30 degrees and a and b are in the same triangle with a 90-degree angle and all interior angles in a triangle equal 180 degrees.
Then, 30+90+b=180
120+b=180
b=60
Angle c and an angle that equals 75 degrees are supplementary. meaning that they add up to 180 degrees.
180-75=c
105=c
1)volume of the pipeline
The pipeline is a cylinder, therefore;
Volume (cylinder)=πr²h
r=radius
h=height of the cylinder
diameter=6 in*(1 ft / 12 in)=0.5 ft
raius=diameter / 2=0.5 ft / 2=0.25 ft.
height=5280 ft
Volume (pipeline)=π(0.25 ft)²(5280 ft)=330π ft³≈1036.73 ft³.
2) we calculate the number of barrel
1 mile of oil in this pipeline is 330π ft³ of oil.
1 barrel of crude------------------5.61 ft³
x----------------------------------330π ft³
x=(1 barrel*330π ft³) / 5.61 ft³=184.8 barrels
3) we calculate the price.
1 barrel---------------$100
184.8 barrels---------- x
x=(184.8 barrels * $100) / 1 barrel=$18,480
Solution: ≈$18,480
Answer:
m<B = 60°
m<C = 60°
m<F = 80°
m<G = 80°
Step-by-step explanation:
m<B = 180° - 120° = 60°
m<C = m<B = 60° (Vertically opposite angles are equal)
m<F = 180° - (40° + m<C(60°)) = 80°
m<G = 180° - (m<H + m<B) = 180° - (40° + 60°) = 80°