Answer:
-1
Step-by-step explanation:
-(-4)-5=
4-5=
-1
Answer:
100 - 2 = 98
$45 = 98
divide both sides by 98 to find the amount of 1%
45/98 =1%
0.45918367 = 1%
now multiply by 100 to find original price
0.45918367 X 100 = 45.92
100% = 45.92
Answer:
0.691
Step-by-step explanation:
Since a percentage means out of 100, divide the percentage by 100
69.1÷100= 0.691
F(-2)=8-10*(-2)=28
g(-2)=5(-2)+4=-6
fg(-2)=168
Answer:
P(B | T)=3/13
Step-by-step explanation:
The question is missing the Venn diagram that shows the value of each variable.
From the Venn diagram we can see there are 10 paintings that not T and not B. That means the total number of paintings that either T or B is
P(T∪B) = 60-10= 50 paintings.
There are x(x-2) + x paintings from 20th century
P(T)= x(x-2) + x = x^2 - x
There are 2x+8 +x British paintings.
P(B)= 2x+8 +x = 3x +8
There are 2 paintings that both T and B
P(T∩B)= x
Using union equation we can find the x
P(T∪B) = P(T) + P(B) - P(T∩B)
50= x^2 - x + 3x +8 - x
x^2 + x + 8 - 50 = 0
x^2 + x + -42 =0
(x-6) (x+7)=0
x1= 6 x2=-7
Since x can't be minus, then x=6.
The question asking how much conditional probability that a random T paintings is also British. The calculation will be:
P(B|T)= P(B∩T) / P(B) = x/ (3x +8)= 6/(6*3+8)= 6/26= 3/13