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Bad White [126]
2 years ago
6

Verify the identity. Justify each step.

Mathematics
1 answer:
ANEK [815]2 years ago
4 0
So. Allow me to justify what i just did.
First line: by definition, tangent in sine/cosine, and cotangent is the reciprocal of that.
Second line: You have to multiply by (\frac{sin cos}{sincos}) to get a common denominator, so you get the second line.
Third line: Canceling stuff out. to get that.
Fourth line: Adding them together since they now have common denominators.
Fifth line: By terms of the pythagorean identity, sin^{2}+cos^{2}=1. so that is equal to the right side. 
Thus verified.

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a cell phone plan offers 250 minutes each month for 15.00 dollars per month. what is the cost per minute when a person uses all
Nezavi [6.7K]
It costs 0.06 cents each minute.

Explanation : $15/250 minutes = $0.06
4 0
3 years ago
Which statements are true for solving the equation 0.5 – |x – 12| = –0.25? Check all that apply.
Trava [24]

we have  

0.5-\left|x-12\right|=-0.25  

we know that        

The absolute value has two solutions

Subtract  0.5 both sides

-\left|x-12\right|=-0.25-0.5  

-\left|x-12\right|=-0.75  

Step 1

Find the first solution (Case positive)

-[+(x-12)]=-0.75

-x+12=-0.75

Subtract  12 both sides

-x+12-12=-0.75-12

-x=-12.75

Multiply by -1 both sides

x=12.75

Step 2

Find the second solution (Case negative)

-[-(x-12)]=-0.75

x-12=-0.75

Adds  12 both sides

x=-0.75+12

x=11.25

<u>Statements</u>

<u>case A)</u> The equation will have no solutions

The statement is False

Because the equation has two solutions------> See the procedure

<u>case B)</u> A good first step for solving the equation is to subtract 0.5 from both sides of the equation

The statement is True ----->  See the procedure

<u>case C)</u> A good first step for solving the equation is to split it into a positive case and a negative case

The statement is False ----->  See the procedure

case D) The positive case of this equation is 0.5 – |x – 12| = 0.25

The statement is False

Because the positive case is 0.5-(x-12)=-0.25 -----> see the procedure

case E) The negative case of this equation is x – 12 = –0.75

The statement is True -----> see the procedure

<u>case F)</u> The equation will have only 1 solution

The statement is False

Because The equation has two solutions------> See the procedure


4 0
3 years ago
Read 2 more answers
in a class experiment, Sean finds that the probability that a student plays soccer is 12/25. if the school population is 300, ho
fgiga [73]

Okay, here we have this:

Considering the provided information, we are going to calculate the requested value, so we obtain the following:

Then we will substitute in the following formula:

Students who play soccer=Number of students*(Probability that they play soccer)

Replacing:

Students who play soccer=300*(12/25)

Students who play soccer=3600/25

Students who play soccer=144

Finally we obtain that 144 students would we expect to play soccer, based on Sean's experiment.

5 0
1 year ago
What is 32 hundreds written in standard form
RoseWind [281]
Standard form means the ordinary number form, like 12, 234, or 150. :)

To find 32 hundreds in standard form, mulitiply 32 * 100 = 3,200

So 32 hundreds in standard form is 3,200.
3 0
2 years ago
Read 2 more answers
Find the value of y and z
elena55 [62]

\qquad\qquad\huge\underline{{\sf Answer}} \huge♨

In the given figure, NQ acts as a diameter and since diameter subtends 90° at the arc of the circle, so we can conclude that ~

\qquad \sf  \dashrightarrow \:3y = 90 \degree

\qquad \sf  \dashrightarrow \:y = 90 \degree \div 3

\qquad \sf  \dashrightarrow \:y = 30 \degree

Now, Let's use Angle sum property of Triangle to solve for z :

\qquad \sf  \dashrightarrow \:4z + 3y + 50 \degree = 180 \degree

\qquad \sf  \dashrightarrow \:4z +90 \degree + 50 \degree = 180 \degree

\qquad \sf  \dashrightarrow \:4z  = 180 \degree  -  (50 \degree  + 90\degree)

\qquad \sf  \dashrightarrow \:4z  = 180 \degree  -  (140\degree)

\qquad \sf  \dashrightarrow \:4z = 40 \degree

\qquad \sf  \dashrightarrow \:z = 40 \degree \div 4

\qquad \sf  \dashrightarrow \:z = 10 \degree

I hope you understood the procedure, you can ask me in comments if you have any doubts.

3 0
2 years ago
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