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Answer:
Step-by-step explanation:
The only graph shown in the question doesn't have amplitude 1/2. look for a graph of a periodic wave function that has maximum y-value 1/2 (0.5) and minimum y-value 1/2 (0.5), or if it is not oscillating around the x-axis, verifies that the distance between minimum y-value and maximum y-value is "1" (one). This is because the amplitude is half of the peak-to-peak distance.
Look at the attached image as example.
*see attachment below for the box plots that is being referred to
Answer:
*The median weight for shelter A is greater than that for shelter B
*The data for shelter B are a symmetric data set
Step-by-step explanation:
Let's take each stated option and examine the box plot to see which is TRUE or NOT.
OPTION 1: "The median weight for shelter A is greater than that for shelter B."
The median for shelter A = 21,
Median for shelter B = 18
Median weight for shelter A (21) is greater than that for shelter B.
This statement in this option is TRUE.
OPTION 2: "The median weight for shelter B is greater than that for shelter A."
Median for B (18) < median of A (21)
This statement in option is NOT TRUE.
OPTION 3: "The data for shelter A are a symmetric data set."
This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.
OPTION 4: "The data for shelter B are a symmetric data set."
This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.
OPTION 5: "The interquartile range for shelter A is 8"
This is NOT TRUE.
IQR = Q3-Q1
IQR for shelter A is approximately = 28-17 = 11
