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ElenaW [278]
3 years ago
11

Please help this is on a quiz

Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0

Answer:

4,5,8,11 are domain

Step-by-step explanation:

Since they are on the x side they are domain

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2k . 9k to the power to -6
xxTIMURxx [149]

1/18k^6 so uhhhh ya laalalallaa

4 0
2 years ago
Help please just answer would be fine
scZoUnD [109]

The amount of water decreases 16\frac{1}{2} pints in 12 weeks.

Solution:

The amount of water decreases in 7 weeks = 9\frac{5}{8} pints

The amount of water decreases each week is same.

Let us first change the mixed fraction into improper fraction.

9\frac{5}{8} pints = \frac{(9\times8)+5}{8}

             =\frac{77}{8} pints

The amount of water decreases in 1 week

              $=\frac{\frac{77}{8} }{7}

              =\frac{77}{8\times7}

              =\frac{11}{8}

So, the amount of water decreases in 1 week is \frac{11}{8} pints.

The amount of water decreases in 12 week

               =\frac{11}{8}\times12

               =\frac{132}{8}

               =16\frac{4}{8}

               =16\frac{1}{2} pints

Hence the amount of water decreases 16\frac{1}{2} pints in 12 weeks.

4 0
3 years ago
What is the distance between the points (0,1) and (8,7)?
andrew11 [14]

Answer:

The answer is 10.

Step-by-step explanation:

4 0
3 years ago
Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
3 years ago
The total mass of 25 candy bars is 2 kilograms. What is the mass of each candy bar in grams?
LuckyWell [14K]
The mass of each candy is 80 grams
3 0
1 year ago
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