Question

What is the equation of the line shown in this graph​

Answer 1

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

The slope is found using the following formula:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

According to the graph we have the following points:

$(x_ {1}, y_ {1}): (-2, -3)\\(x_ {2}, y_ {2}) :( 3, -3)$

Substituting we have:

$m = \frac {-3 - (- 3)} {3 - (- 2)} = \frac {-3 + 3} {3 + 2} = \frac {0} {5} = 0$

Therefore, the line is of the form:

$y = 0x + b\\y = b$

We find "b" replacing the coordinate "y" of a point:

$-3 = b$

Thus, the equation is:

$y = -3$

Answer:

$y = -3$