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3 years ago

T/F The range of a function is the set of all its inputs

2 answers:

6 0

True, the range of a function is the set of all its inputs. The range of a discrete function would be written like: $[ y_{1}, y_{2}, y_{3}, y_{4} ]$ , while the range of a continuous function would be written like: $(y_{0}, y_{n})$

Pavlova-9 [17]3 years ago

3 0

False, the range of a function is not the set of all its inputs.

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Find the number that belongs in the green box. Round your answer to the nearest tenth.

Alisiya [41]

I think the answer is 20

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2 years ago

A store sells almonds for $7 per pound, cashews for $10 per pound, and walnuts for $12 per pound. A customer buys 12 pounds of m

shepuryov [24]

Answer:

Step-by-step explanation:

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2 years ago

HELP ME IM SO CONFUSED

givi [52]

Answer:

1) 4812 students
2) 763 pounds
3) $30906.76

Step-by-step explanation:

Initial number = 2988
Rate of increase = 10%

Number of students after 6 years:

$a_6 = 2988(1+0.1)^{6-1} = 4812$

Initial number = 1200
Rate of decrease = 14%

Amount of gold after 4 years:

$a_4=1200(1-0.14)^3 = 763$

Initial number = 28000
Rate of increase = 2.5%

Salary after n years:

$a_n=28000(1+0.025)^{n-1} = 28000*1.025^{n-1}$

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6 0

2 years ago

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Ksivusya [100]

Answer:

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Step-by-step explanation:

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2 years ago

Find the next 3 terms in the geometric sequence -36, 6, -1, 1/6, ...

timama [110]

we are given

geometric sequence -36, 6, -1, 1/6, ...

first term is -36

$a_1=-36$

now, we can find common ratio

$r=\frac{6}{-36}$

$r=-\frac{1}{6}$

now, we can find nth term

$a_n=a_1(r)^{n-1}$

now, we can plug values

and we get

$a_n=36(-\frac{1}{6})^{n-1}$

now, we can find 5th term , 6th term, 7th term

fifth term:

$a_5=36(-\frac{1}{6})^{4}$

$a_5=\frac{1}{36}$

sixth term:

$a_6=36(-\frac{1}{6})^{5}$

$a_6=-\frac{1}{216}$

seventh term:

$a_7=36(-\frac{1}{6})^{6}$

$a_7=\frac{1}{1296}$

so, next terms are

$a_5=\frac{1}{36}$ , $a_6=-\frac{1}{216}$

, $a_7=\frac{1}{1296}$ .............Answer

6 0

3 years ago