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egoroff_w [7]
4 years ago
7

In a rectangular prism, V = bwh. Solve for h

Mathematics
1 answer:
Verizon [17]4 years ago
4 0
The answer to the question

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Calendario matematico la necesito ya porfa.
Murrr4er [49]

The common difference based on the sequence given is 15.

<h3>How to illustrate the sequence?</h3>

It should be noted that the sequence given Isa arithmetic sequence.

The common difference will be the second term minus the first term. This will be:

= 101 - 86

= 15

In conclusion, the difference is 15.

Learn more about sequence on:

brainly.com/question/6561461

#SPJ1

8 0
2 years ago
There are 180 cars in the parking lot 30% are red cars how many red cards are there
Yuri [45]
There are 54 red cars
7 0
2 years ago
Read 2 more answers
Write 240 and 1500 as products of their prime factor
Marina CMI [18]
240 = 2 × 120
120 = 2 × 60
60 = 2 × 30
30 = 2 × 15
15 = 3 × 5
The 2, 2, 2, 2, 3 and 5 are all the prime factors of 240. So, 2^4 × 3 × 5

1500 = 3 × 500
500 = 5 × 100
100 = 5 × 20
20= 5 × 4
4 = 2 × 2
The 3, 5, 5, 5, 2 and 2 are all the prime factors of 1500. So, 2² + 3 + 5³
4 0
3 years ago
Read 2 more answers
A metalworker has a metal alloy that is 15​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
coldgirl [10]

18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

but

x + y = 90

x= 90 - y

substituting that value in for x

0.15(90 - y) + 0.60y = 45.9

13.5 - 0.15y + 0.60y = 45.9

0.45y = 32.4

y = 72

Substituting this y value to solve for x gives:

x + y = 90

x= 90-72

x=18

Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.

6 0
3 years ago
Describe a process you would use to create the perpendicular bisector to a segment AB using only an unmarked straightedge and an
Murrr4er [49]

You'll have to c<span>ompass tip on A and draw a small ark with pencil approximately in the middle above AB line, now compass tip to point B and cross the ark you made previously.
Do the same on the opposite side without making any change to the compass 
Join the lines where crosses of arks on the both side meet and then ,it's done.</span>
8 0
3 years ago
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