140 pounds * 6 feet = 112 pounds * x feet
x feet = (140 * 6) / 112
x = 7.5 feet
Step-by-step explanation:
Since both lines intersect each other 3 units above the x-axis, the y-value of the point of intersection must be 3.
Looking at the options, (-3, 5), (3, -2) and (0, -3) are all invalid points.
Answer:
Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is
Step-by-step explanation:
Evaluate:
When a=-4, b=2, c=-3, and d =4
Solution:
Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get
Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is
The key features of a quadratic graph that can identified are; x and y intercepts, axis of symmetry and vertex
<h3>Keys features of a quadratic graph</h3>
The key features are the x-intercepts, y-intercepts, axis of symmetry, and the vertex.
If we add units we can move this function upwards, downwards leftwards and rightwards.
- If we add a positive number to the x-variable, then the graph will move to the left.
- If we add a negative number to the x-variable, then the graph will move to the right.
- If we add a positive number to y-variable, then the graph will move upwards.
- If we add a negative number to y-variable, then the graph will move downwards.
Hence, if we compare the rules we use before with linear function, there's no distinction between horizontal and vertical movements, because if we add to x-variable, then y-variable will be also affected.
Learn more about quadratic graphs here:
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Step-by-step explanation:
Take the first derivative
Set the derivative equal to 0.
or
For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).
For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.
Since we are going to Positve to negative slope, we have a local max at x=-1
Plug in -1 for x into the original function
So the local max is 2 and occurs at x=-1,
For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.
Since we are going to decreasing to increasing, we have minimum at x=1,
Plug in 1 for x into original function
So the local min occurs at -2, at x=1
