Question

Which equation represents the general from a circle with the center at (-2,-3) and a diameter of 8 units ?

Answer 1

Answer:

$(x+2)^2 + (y+3)^2 = 16$

Step-by-step explanation:

To write the equation of a circle, use the formula $(x-h)^2+(y-k)^2 = r^2$ where the center of the circle is (h, k).

This means the equation is $(x--2)^2 + (y--3)^2 = r^2\\\\(x+2)^2+(y+3)^ = r^2$.

Since the diameter is 8, the radius will be 4.

The equation is $(x+2)^2 + (y+3)^2 = 16$.