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Elza [17]
3 years ago
11

What is the quotient of|x+3x-4x-121-+5x+ 6l2x+228x+8​

Mathematics
1 answer:
Elena-2011 [213]3 years ago
6 0

Answer:

6xl2 + 223x - 113

Step-by-step explanation:

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Plz help
Yuliya22 [10]

Answer:

Solution: x = 2, y = -1 or (2, -1)

Step-by-step explanation:

Equation 1:  2x + y = 3

Equation 2: 5x - 2y = 12

Using the substitution method:

Transform the Equation 1 into its slope-intercept form:

2x + y = 3

2x - 2x + y = -2x + 3

y = 2x + 3

Substitute the value of y = -2x + 3 into Equation 2:

5x - 2y = 12

5x - 2(-2x + 3) = 12

5x + 4x - 6 = 12

9x - 6 = 12

9x - 6 + 6 = 12 + 6

9x = 18

9x/9 = 18/9

x = 2

Substitute the value of x = 2 into Equation 2 to solve for y:

5x - 2y = 12

5(2) - 2y = 12

10 - 2y = 12

10 - 10 - 2y = 12 - 10

-2y = 2

-2y/-2 = 2/-2

y = -1

Double-check whether the values for x and y will provide a true statement for both equations:

Equation 1:  2x + y = 3

2(2) + (-1) = 3

4 - 1 = 3

3 = 3 (True statement)

Equation 2: 5x - 2y = 12

5(2) - 2(-1) = 12

10 + 2 = 12

12 = 12 (True statement)

Therefore, the correct answers are: x = 2; y = -1 or (2, -1).

4 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Tju [1.3M]

Answer:

-10 because you do parenthesis first

4 0
3 years ago
Read 2 more answers
In the past month, Josh rented one video game and six DVDs. The rental price for the video game who is $2.50. The rental price f
dolphi86 [110]

Answer:

total amount paid = $ 22.9

Step-by-step explanation:

total price = $ 2.5 + $3.4(6)= $22.9

5 0
3 years ago
Read 2 more answers
An office building casts a 90 foot shadow. At the same time of day, a 5 foot woman standing near the building casts an 8 foot sh
Rainbow [258]
The building is about 56 feet tall
8 0
2 years ago
Read 2 more answers
| x-3 | &lt; x-3<br><br> can someone give a step by step process on how to do this?
statuscvo [17]

Answer:

There are no solutions to the inequality.

Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)  

2. Solve each equation separately

(a) Equation (1)

\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}

(b) Equation (2)

\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &

For example, if x = 0, we get  

|0 - 3| < 0 - 3 or

3 < -3

4 0
3 years ago
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