2 years ago

Find the surface area of the rectangular prism. 8 m 4 m 1 m

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

5 0

Answer:

A=2(wl+hl+hw)

Step-by-step explanation:

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3 years ago

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vladimir1956 [14]

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3 years ago

Match the graph given to the right to its function.

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1 year ago

What is the inverse and restricted domain of the equation 8x^2-3

kari74 [83]

Answer: $\bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}$

Step-by-step explanation:

y = 8x² - 3 (Restriction: none - x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3 swapped the x and y

x + 3 = 8y² added 3 to both sides

$\dfrac{x+3}{8}=y^2$ divided both sides by 8

$\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}$ square rooted both sides

$\pm \sqrt{\dfrac{x+3}{8}}=y$ simplified

$\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y$ rationalized the denominator

$\pm \sqrt{\dfrac{2(x+3)}{16}}=y$ simplified

$\pm \dfrac{\sqrt{2(x+3)}}{4}=y$ simplified

Restriction:

The radical (inside the square root sign) cannot be negative

→ 2(x + 3) ≥ 0

x + 3 ≥ 0 divided both sides by 2

x ≥ -3 subtracted 3 from both sides

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3 years ago

1/8 , -0.333, - 1/7 , - 4/9 Put these numbers in order from LEAST to GREATEST

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-4/9, -0.333, -1/7, 1/8

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3 years ago