Ok? Where’s the rest of the question.
Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
Answer:
8
Step-by-step explanation:
-(5 – 9) - (-2)(2)
-(-4) - (-2)(2)
4 - (-4)
4 + 4
8
Use PEMDAS
First let's solve for the rate, "b", by setting up a ratio with the two points given:
16.875/7.5=(ar^3)/(ar)
2.25=r^2
r=1.5
Now we need to solve for the initial value a using either point given...
7.5=a(1.5)^1
7.5=1.5a
a=5
So now we have solved for both variables and have a complete equation:
y=5(1.5)^x