3 years ago

Express ' in seconds.30"NEXT QUESTION© ASK FOR HELP

Mathematics

1 answer:

jonny [76]3 years ago

5 0

Answer:

30 seconds

Step-by-step explanation:

You add seconds at the end.

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Move all the terms involving the sine to one side, and all the numbers to the other:

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3 years ago

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Answer:

Step-by-step explanation:

$LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS$

Hint: 1 - Cos² A = Sin² A

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3 years ago

Express ' in seconds.30"NEXT QUESTION© ASK FOR HELP​

Express ' in seconds.30"NEXT QUESTION© ASK FOR HELP