Answer:
- h = 0 when the ball hits the ground
- about 3.464 seconds
Step-by-step explanation:
The formula gives h = 192 when t=0, so we assume that h represents the height above the ground. The ball will have a height of 0 when it hits the ground.
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Using that in the equation, we can solve for t.
0 = 192 -16t^2
0 = 12 -t^2 . . . . . . divide by 16
t^2 = 12 . . . . . . . . add t^2
t = √12 = 2√3 ≈ 3.464 . . . . take the square root
It will take 2√3 seconds, about 3.464 seconds, for the ball to hit the ground.
Answer:
The diagram of the plotting point
is attached below.
Step-by-step explanation:
Given the points

as


so the point can be visualized as:

Now, we can check the point x = 3.5, and determine the corresponding value y = 2.75 and plot the point at the location (x, y) = (3.5, 2.75)
The diagram of the plotting point
is attached below.
Answer:
poop
Step-by-step explanation:
Answer:
Answer is A
A contains all the elememts common to both the sets and thus it is the inteesection of the given two sets.
I hope this helps you
#Indian : )
Answer:
<h3>5</h3>
Step-by-step explanation:
Given the expression
2a^3−10ab^2+3a^3−ab^2−7
We are to find the coefficient of a^3
First is to collect the like terms;
2a^3−10ab^2+3a^3−ab^2−7
= 2a^3+3a^3−10ab^2−ab^2−7
= 5a^3-11ab^2-7
From the resulting equation, you can see that the coefficient of the term having a^3 is 5