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svp [43]
4 years ago
11

How do I graph this equation? y = -7/3x + 2

Mathematics
1 answer:
Molodets [167]4 years ago
5 0
I can think of two ways to do it.

Way #1:

-- Pick a number.
   Write it in place of 'x', and calculate the value of 'y'.
   Call these 'x₁' and 'y₁'.

-- Pick another number.
   Write it in place of 'x', and calculate the value of 'y'.
   Call these 'x₂' and 'y₂'.

-- On your graph, mark little dots at the points (x₁, y₁) and (x₂, y₂).

-- With your ruler and pencil, draw a straight line between the two dots.
   Then extend it as far as you want to in each direction.

The line you drew is the graph of the equation.  
________________________________________

Way #2:

-- Looking at the equation, you realize that the slope of the graph is -7/3,
   and its slope is 2 .  Use this powerful information to draw the graph.

-- Mark a little dot on the y-axis, at the point where  y = 2 .

-- From that point, move your eyes 7 units to the right, then 3 units down,
   and mark a little dot where you land.

-- With your ruler and pencil, draw a straight line between the two dots.
   Then extend it as far as you want to in each direction.

The line you drew is the graph of the equation.  
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PLEASE PLEASE HELP <3
anzhelika [568]

Answer:

C

Step-by-step explanation:

∠ AFD = ∠ AFB + ∠ BFC + ∠ CFD

The 3 angles form a straight angle and sum to 180°, that is

4x + 5 + 6x + 3 + 5x + 7 = 180, that is

15x + 15 = 180 ( subtract 15 from both sides )

15x = 165 ( divide both sides by 15 )

x = 11

∠ CFD = 5x + 7 = 5(11) + 7 = 55 + 7 = 62°, thus

∠ AFE = ∠ CFD = 62° ( vertical angles are congruent )

3 0
3 years ago
Question 3 (open to see pic)
melamori03 [73]
The points (1,-2) and (4,16) are not in the line but the point (-3,-18) is on the line. (Work is shown in the image)

8 0
3 years ago
Find the sum. <br> 8 + -1 + -5<br><br> A. 2<br> B. 14<br> C. -2<br> D. 16
Yanka [14]

Answer:

a

Step-by-step explanation:

-1 0 1 2 3 4 5 6 7 8 9

1. 2. 3. 4 5 6 7 8 therefore its 7

-5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9

1. 2. 3. 4. 5 6 7 so the answer is a 2

7 0
3 years ago
Read 2 more answers
Find, corrrect to the nearest degree, the three angles of the triangle with the given vertices. D(0,1,1), E(-2,4,3), C(1,2,-1)
Sholpan [36]

Answer:

The three angles of the triangle given above are 23, 73 and 84 correct to the nearest degree. The concept of dot product under vectors was applied in solving this problem. The three positions forming the triangle were taken as positions vectors. The Dot product also known as scalar product is a very good way of finding the angle between two vectors. ( in this case the sides of the triangle given above). Below is a picture of the step by step procedure of the solution.

Step-by-step explanation:

The first thing to do is to treat the given positions in space as position vectors which gives us room to perform vector manipulations on them. Next we calculate the magnitude of the position vector which is the square root of the sun of the square of the positions of the vectors along the three respective axes). Then we calculate the dot product. After this is calculated the angle can then be found easily using formula for the dot product.

Thank you for reading this and I hope it is helpful to you.

4 0
4 years ago
Explain how to find the sides of a 45° - 45° - 90° triangles:
ollegr [7]
Opposite of 90* would be equivalent to the square root of the other sides

4 0
3 years ago
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