A great circle is a section of a sphere that passes through its center. If the earth were a sphere, a great circle would be the equator and its axis would be the line connecting the geographic north and south pole. The length of the axis is then equal to the diameter of the sphere. For this problem, the radius of the sphere is 12 inches. A section is formed by slicing through the sphere and all sections of a sphere are circles. Considering the plane to be cut above and parallel with the equator (which is a great circle), the distance of the plane from the center of the sphere would then be the distance between the centers of the sphere and section. It is also given that the radius of the section is 9 inches. A right triangle is formed by connecting the center of the sphere, an edge of the section, and back to the center of the sphere whose hypotenuse is 12 inches (radius of the sphere), one leg is the 9 inches (radius of the section), and another leg is the distance of the plane from the sphere's center. Thus, the distance can be calculated using the Pythagorean theorem, d = sqrt(12^2 - 9^2) = sqrt(144 - 81) = sqrt(63) = 3*sqrt(7).
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Answer:
rewrite each sentence change the underline word (s) to a pronoun my friends and i are going to the movies
Answer:
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Step-by-step explanation:
we know that
The scale of the drawing is equal to divide the length of a building in the scale drawing by the actual length of a building
so
That means
15 cm in the drawing represent 37.5 ft in the actual
Remember that
Convert 15 cm to ft
divide by 30.48
substitute
or
That means
1.31 units in the drawing represent 100 units in the actual
210 take 126/3 = 42 take 42x5 = 210
<u>Given</u>:
The equation of the circle is 
We need to determine the center and radius of the circle.
<u>Center</u>:
The general form of the equation of the circle is 
where (h,k) is the center of the circle and r is the radius.
Let us compare the general form of the equation of the circle with the given equation to determine the center.
The given equation can be written as,
Comparing the two equations, we get;
(h,k) = (0,-4)
Therefore, the center of the circle is (0,-4)
<u>Radius:</u>
Let us compare the general form of the equation of the circle with the given equation to determine the radius.
Hence, the given equation can be written as,
Comparing the two equation, we get;
Thus, the radius of the circle is 8
