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gulaghasi [49]
4 years ago
6

What kind of reaction occurs when potassium is placed in water? a. a single-displacement reaction c. a decomposition reaction b.

a double-displacement reaction d. electrolysis
Physics
1 answer:
satela [25.4K]4 years ago
7 0
The equation for potassium in water is:
K(s) + H20(l) --> H2(g) + K20(aq)
since a element and a compound are reacting, this is a single replacement reaction - which is a)
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Air enters the diffuser of a jet engine operating at steady state at 18 kPa, 216 K and a velocity of 265 m/s, all data correspon
earnstyle [38]

Answer:

45.44m/s

Explanation:

To solve this problem it is necessary to go back to the concepts related to the first law of thermodynamics,

in which it deepens on the conservation of the Energy.

The first law of Thermodynamics is given by the equation:

0 = \dot{Q}-\dot{W}+\dot{m}(h_1-h_2)+\dot{m}(\frac{V_1^2-V^2_2}{2})+\dot{m}g(z_1-z_2)

Where,

\dot{Q}= Heat transfer

\dot{W} =Work

\dot{m} =Flow mass

V_i =Velocity

h_i = Specific Enthalpy

g =Gravity

z_i =Height

From this equation we have that there is not Heat transfer, Work and changes in Height. Then,

Then our equation would be,

0=\dot{m}(h_1-h_2)+\dot{m}(\frac{V_1^2-V^2_2}{2})

Solving for V_2,

V_2 = \sqrt{V_1^2+2(h_1-h_2)}

From the tables of ideal gas (air) at 216K we have,

h_1 = 209.97+(219.97-209.97)(\frac{216-210}{220-210})

h_1 = 215.97kJ/kg

From the tables at 250K, we have that

h_2 = 250.05kJ/kg

The velocity was previously given, then

V_1 =265m/s

Replacing in the equation:

V_2 = \sqrt{265^2+2(215.97-250.05)*10^3}

V_2 = 45.44m/s

Therefore the velocity of the air at the diffuser exit is 45.44m/s

3 0
4 years ago
A 1000 kg elevator is accelerated upward at a rate of 0.70 m/s2. What is the tension in the cable pulling the elevator upward wh
Masteriza [31]

Answer:

Tension is also known as Force...

and Force is mass× acceleration.

so....1000×0.70=700N

5 0
4 years ago
Read 2 more answers
A heavy mirror that has a width of 2 m is to be hung on a wall as shown in the figure below. The mirror weighs 700 N and the wir
loris [4]

The translational equilibrium condition allows finding that the response for cable length with a maximum tension is

      L = 2.56 m

Newton's second law says that the force is proportional to the mass and the acceleration of the body, in the special case that the acceleration is zero, the relationship is called the translational equilibrium condition.

              ∑ F = 0

 

Where the bold indicates vectors, F is the force and the sum is for all external forces.

The reference systems are coordinate systems with respect to which the decomposition of the vectors is carried out and the measurements are made, in this case we will use a system with the horizontal x axis and the vertical y axis.

In the attachment we can see a free body diagram of the system, let's write the equilibrium condition for each axis.

x-axis  

         Tₓ -Tₓ = 0

y-axis

         T_y + T_y - W =0

         2T_y - W = 0

Let's use trigonometry to decompose the tension, we can see from the graph and the adjoint that each string is half the length, let's call the angle θ

          cos θ = \frac{T_x}{T}

          sin θ = \frac{T_y} { T}

          Tₓ = T cos θ

          T_y = T sin θ

We substitute

          2 T sin θ = W          (1)

The text indicates that the length of the block is 2 m, so the distance to the midpoint is

        x = 1 m

Let's use the Pythagoras' Theorem            

            H² = CA² + CO²

           CO = \sqrt{H^2 - CA^2}

           CA = x

           CO = \sqrt{(\frac{L}{2} )^2  - 1 }

Where CO is the opposite leg,  CA is the adjacent leg and H is the hypotenuse indicating H = L / 2,

Let's write the trigonometry functions

           sin θ = \frac{CO}{H}

Let's substitute        

            sin θ = \frac{2 \sqrt{\frac{L^2}{4} -1 } }{L}

Let's subtitute in the equation  1

          2 T  ( \frac{2 \sqrt{\frac{L^2}{4} -1 } }{L}   ) = W

          \sqrt{\frac{L^2}{4}-1  }  = \frac{1}{4}  \ \frac{W}{T} \ L

Let's solve by squaring

         \frac{L^2}{4}  -1 = \frac{1}{4} \ (\frac{W}{T} )^2 \ \frac{L^2}{4}  

         \frac{L^2}{4} ( 1 - \frac{1}{4} (\frac{W}{T})^2  ) -1 =0

They indicate that the maximum tension of the cable is T = 700N and the weight is worth W = 700N, we substitute the values

        \frac{L^2}{4} ( 1- \frac{1}{4}) - 1 =0 \\\frac{3 L^2}{16} = 1 \\ L^2 = \frac{16}{3} \\L = \sqrt{\frac{16}{3} }

        L =   2.31 m    

In conclusion using the translational equilibrium condition we can find that the response for cable length with maximum tension is

      L = 2.31 m

Learn more about translational equilibrium here:

brainly.com/question/12966823

7 0
3 years ago
Read 2 more answers
A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a
avanturin [10]
<span>The answer to your question is choice: D</span>
8 0
3 years ago
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How do you find the volume of a lead ball if the mass is 454 grams?
inna [77]
By doing this in your calculator:  4/3 times <span>π and 454 to the third power. good luck :)</span>
4 0
3 years ago
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