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3 years ago

Two objects of masses m1 = 0.56 kg and m2 = 0.88 kg are placed on a horizontal

Physics

1 answer:

ziro4ka [17]3 years ago

3 0

Explanation:

Stern et al. (1999) and Stern (2000), define this variable as those general visions about the world, reflected in the beliefs that people express about their relationship with the environment and nature.हेलो फ्रेंड्स मारो किसी को इनबॉक्स कैसे करें

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S.I unit for moment of inertia of a fly wheel

qaws [65]

Answer:

m is expressed in kilograms and r in metres, with I (moment of inertia) having the dimension kilogram-metre square.

8 0

2 years ago

An electron in a vacuum is first accelerated by a voltage of 51400 V and then enters a region in which there is a uniform magnet

zimovet [89]

Answer:

F = 8.6 10⁻¹² N

Explanation:

For this exercise we use the law of conservation of energy

Initial. Field energy with the electron at rest

Em₀ = U = q ΔV

Final. Electron with velocity, just out of the electric field

Emf = K = ½ m v²

Em₀ = Emf

e ΔV = ½ m v²

v =√ 2 e ΔV / m

v = √(2 1.6 10⁻¹⁹ 51400 / 9.1 10⁻³¹)

v = √(1.8075 10¹⁶)

v = 1,344 10⁸ m / s

Now we can use the equation of the magnetic force

F = q v x B

Since the speed and the magnetic field are perpendicular the force that

F = e v B

F = 1.6 10⁻¹⁹ 1.344 10⁸ 0.4

For this exercise we use the law of conservation of energy

Initial. Field energy with the electron at rest

Emo = U = q DV

Final. Electron with velocity, just out of the electric field

Emf = K = ½ m v2

Emo = Emf

.e DV = ½ m v2

.v = RA 2 e DV / m

.v = RA (2 1.6 10-19 51400 / 9.1 10-31)

.v = RA (1.8075 10 16)

.v = 1,344 108 m / s

Now we can use the equation of the magnetic force

F = q v x B

Since the speed and the magnetic field are perpendicular the force that

F = e v B

F = 1.6 10-19 1,344 108 0.4

F = 8.6 10-12 N

5 0

3 years ago

Lyrx [107]

Answer:

ion know tbh

Explanation:

7 0

3 years ago

Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.80 nC, are separated by a dista

soldi70 [24.7K]

Answer:

$v = 7793150 m/s$

Explanation:

First, we are going to calculate the electrical potential in the point middle between the two charges

Remember that the electrical potential can be calculated as:

$v = \frac{kQ}{r}$

Where $k = 8.9874 x 10^{9} \frac{Nm^{2} }{C^{2} }$

and it is satisfy the superposition principle, thus

$v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.23} + \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.23}$

$v = 222.73v$

The electrical potential at 10 cm from charge 1 is:

$v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.1} + \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.36}$

$v = 395.44 v$

Since the work - energy theorem, we have:

$q\Delta v = \frac{mv^{2} }{2}$

where q is the electron's charge and m is the electron's mass

Therefore:

$v = \sqrt{\frac{2q\Delta v}{m} }$

$v = 7793150 m/s$

6 0

3 years ago

The world's fastest production sportscar has a top speed of 415 kmh-1(a)Convert this speed to ms-1.[ 1](b)The distance from Lond

Alex73 [517]

Answer:

(a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

Explanation:

Given that,

Top speed = 415 km/h

1 miles = 1609 m

(a). We need to calculate the speed in m/s

Using conversion of km/h to m/s

$v=415\ km/h$

$v=415\times\dfrac{5}{18}$

$v=115.28\ m/s$

(b). We need to calculate the distance from London to Edinburgh in km

Using conversion for distance

$d=403\ miles$

Distance in meter,

$d=403\times1609$

$d=648427\ m$

$d=648.427\ km$

We need to calculate the time

Using formula of time

$t=\dfrac{d}{v}$

Put the value into the formula

$t=\dfrac{648.427}{415}$

$t=1.56\ h$

$t=1\ hours 34\ min$

$t= 94\ min$

(c). Speed v' =7.66 km/s

v'=7660 m/s

In the time it takes the car to travel from London to Edinburgh,

We need to calculate the distance

Using formula of distance

$d'=v'\times t$

Put the value into the formula

$d'=7660\times94\times60$

$d'=43202400\ m$

$d'=43202.400\ km$

(d). Speed :

Speed is equal to the distance divided by time.

It is scalar quantity.

Velocity :

Velocity is equal to the displacement divided by time.

It is vector quantity.

Hence, (a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

3 0

3 years ago