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Georgia [21]
4 years ago
10

Which best describes a chain reaction associated with a nuclear reaction?

Physics
1 answer:
mojhsa [17]4 years ago
8 0
I think fission chain reaction is the correct answer.
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In a circuit, three pieces of wire labeled A, B and C are joined at a common point, D. If wire B carries 1.5 mA in a direction a
Alex_Xolod [135]

Answer:

correct option is a. 0.2 mA toward D

Explanation:

given data

B carries = 1.5 mA

C carries current  = 1.3 mA

solution

we take positive direction of current going away from the point D

and negative direction of current coming towards point D

so we use here kirchoff's current law   that is

iA + iB + iC = 0    ......................1

iA + 1.5 + (-1.3) = 0

iA = - 0.2 mA  

so that current in wire A is 0.2 mA towards point D

correct option is a. 0.2 mA toward D

7 0
3 years ago
Two identical vertical springs S1 and S2 have masses m1 = 400 g and m2 = 800 g attached to them. If m1 causes spring S1 to stret
OlgaM077 [116]

Answer:

potential energy = mgh

= 400÷1000 × 10× 4÷100

= 0.4 × 10 × 0.04

=4/10 ×10×4/100

= 4/10 × 4/10

=16/100

= 0.16 joules

m1 (400) stretches 4cm

m1 (100g) stretches 1cm

so, m2(800g) stretches 8 cm

potential energy of m2 = mgh

= 800/1000 ×10×8/100

= 0.8 × 0.8

=8/10 ×8/10

= 64/100

=0.64 joules

Ratio of s1 to s2

16/100 ÷ 64/100

= 1:4 ( answer)

6 0
2 years ago
Anthony walks to the pizza place for lunch. He walks 1km east, and then 1 km east again. What distance did he cover? What was hi
Nady [450]

Answer:

Distance covered by Anthony is 3 km. Don't know about displacement though.

3 0
3 years ago
The invention of the microscope made it possible for people to discover
sineoko [7]
The answer is D. They already knew about animals, plants and skin.
5 0
3 years ago
Read 2 more answers
A coil of conducting wire carries a current of i(t) = 14.0 sin(1.15 ✕ 103t), where i is in amperes and t is in seconds. A second
Advocard [28]

Answer:

The peak emf in second coil is 1.876 V

Explanation:

Given :

Inductance L = 130 \times 10^{-6} H

The current I(t) = 14 \sin(1.15\times 10^{3} t)

We compare above equation with standard equation,

  I(t) = I_{o} \sin (\omega t + \phi)

From above equation we have,

  \omega = 10^{3} and \phi = 1.15

Find the inductive resistance,

  X_{L} = \omega L

  X_{L} = 10^{3}  \times 130  \times 10^{-6}

  X_{L} = 0.134

The peak emf in second coil is,

   V = I_{o} X_{L}

  V = 14 \times 0.134

  V = 1.876 V

Therefore, the peak emf in second coil is 1.876 V

8 0
3 years ago
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