This sine function has the form y = f(x) = a sin (bx + c), where |a| is the amplitude, b is the frequency, and c determines the phase shift.
The period of this sine curve is 2 pi/b, or (in this problem) 2 pi/(1/2).
The phase shift of this curve is -c/b, or -(pi/4)/(1/2). Simplify this.
The amplitude is |-3|, or just 3.
Draw a set of coordinate axes. Draw light horizontal lines through y=3 and y=-3. These are the max and min. values of this sine function.
Plot the phase shift on your x-axis.
Your sine function will begin at (phase shift value, 0) and continue for one period. Add the period to the phase shift value. Draw a sine curve beginning and ending at these two x-values.
I encourage you to share your calculations and to sketch the graph described here. Then I could give you more specific feedback on your work. Good luck!
Answer:
150 degrees
Step-by-step explanation:
90+30=120.
Since angle afc is bisected by line bf, that means that the angles formed equal each other. Since the total angle measurement is 180 degrees, we do 180-120=60. 60/2=30. 120+30=150 degrees.
Instead of distributing 2, we can actually divide both sides by 2:
x - 1 = 2x - 11
Isolate x:
x = 10
Answer: 7
Step-by-step explanation:
6-4x-5x=-57
6 -9x= -57
9x= 57+6
9x= 63
Divide both sides by 9
x= 7
Answer:
Step-by-step explanation:
when you put it into slope intercept form you get
y=2x-3
2 is the slope, so
y=2x+3 would have the same slope which means these lines are parallel.
