Answer:
P( top two horses are predicted incorrectly in incorrect order)
=
Step-by-step explanation:
In the horse race the outcome can be predicted in 5! = 120 ways.
Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the top horse can be predicted incorrectly in 4 ways.
Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5
so the second horse can be predicted to be in place from 1 to (k - 1)
So, the top two horses can be predicted incorrectly in incorrect order
in = 10 ways
and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.
Hence ,
P( top two horses are predicted incorrectly in incorrect order)
=
=
<h3>
Answer: 5 < x < 21</h3>
Explanation:
Let x be the length of the third side. We can't find the exact value of x, as we don't have enough info, but we can find possible values for x.
The lower boundary for x is 13-8 = 5. It must be larger than this value.
At the same time, x must be smaller than 13+8 = 21 as well.
So x > 5 and x < 21 becomes 5 < x < 21
In short, x is between 5 and 21. It cannot equal either endpoint.
Your inequality looks like this:
To get rid of the /6, you need to multiply by 6 as the opposite operation cancels it out. So, all you need to do is multiply both sides by 6 to isolate x.
Therefore: