Suppose that Aces can be either high or low; that is, that {A, 2, 3, 4, 5} is a straight, and so is {10, Jack, Queen, King, Ace}
zmey [24]
The probability of being dealt a five card hand that is two pair from a well shuffled standard deck of cards is 40.
According to the statement
I have 10 starting cards, from Ace to 10, and 4 suits,
and by this way we get the 40 subsets and because of these subsets there is a probability becomes 40.
So, The probability of being dealt a five card hand that is two pair from a well shuffled standard deck of cards is 40.
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Answer:
fourth option
Step-by-step explanation:
note that (
)(x)x) = 
=
← factorise numerator/ denominator
=
← cancel the common factor (2x + 1)
=
where x ≠ 0, - 
Square root 320 can be factorised into root64 x root5, and root64 is 8, so the answer is 8root5
It's a 50 50 chance since 3 2s and 2 3s plus there are 8 numbers which isn't in the 3s favor so because there 8 numbers and only 3 2s