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Flauer [41]
3 years ago
11

The length of the hypotenuse of 30 -60 -90 triangle is 4 find the longer leg

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0
The longer leg is the leg adjacent to the larger angle

so 60 

length of longer leg = 4 sin60 = 2sqrt(3) 

Veronika [31]3 years ago
7 0

Answer:

2\sqrt{3} units is the longer leg

Step-by-step explanation:

Definition: 30 -60 -90

In 30-60-90 triangle,

the length of the hypotenuse is twice the length of the shorter leg; and

the length of the longer leg is \sqrt{3} times the length of the shorter leg.

As per the statement:

The length of the hypotenuse of 30 -60 -90 triangle is 4

Length of hypotenuse = 4 units

then, by definition we have;

length of shorter leg = 2 units

then;

the length of the longer leg is \sqrt{3} times the length of the shorter leg.

⇒Length of longer leg = 2\sqrt{3} units

Therefore, the length of longer leg is, 2\sqrt{3} units

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The costs of different weights of onions sold at a grocery store are shown in the table below. What are the independent and depe
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Answer:

Independant = onions wight. Dependent = cost.

Step-by-step explanation: The Cost depends on how much the onions weight.

3 0
3 years ago
Help pls haha also Merry Christmas
MArishka [77]

Answer:

x = √39

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Identify</u>

Leg <em>a</em> = <em>x</em>

Leg <em>b</em> = 5

Hypotenuse <em>c</em> = 8

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [PT]:                     x² + 5² = 8²
  2. Isolate <em>x</em> term:                       x² = 8² - 5²
  3. Exponents:                            x² = 64 - 25
  4. Subtract:                               x² = 39
  5. Isolate <em>x</em>:                               x = √39
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3 years ago
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He normal pulse rate of a 13-year-old is between 70 and 100 beats per minute. As part of a health program, the medical staff at
SVEN [57.7K]
From the box plot, it can be seen that for grade 7 students,
The least value is 72 and the highest value is 91. The lower and the upper quartiles are 78 and 88 respectively while the median is 84.

Thus, interquatile range of <span>the resting pulse rate of grade 7 students is upper quatile - lower quartle = 88 - 78 = 10

</span>Similarly, from the box plot, it can be seen that for grade 8 students,
The least value is 76 and the highest value is 97. The lower and the upper quartiles are 85 and 94 respectively while the median is 89.

Thus, interquatile range of the resting pulse rate of grade 8 students is upper quatile - lower quartle = 94 - 85 = 9

The difference of the medians <span>of the resting pulse rate of grade 7 students and grade 8 students is 89 - 84 = 5

Therefore, t</span><span>he difference of the medians is about half of the interquartile range of either data set.</span>
6 0
3 years ago
Read 2 more answers
A, B &amp; C form a triangle where ∠ BAC = 90°. AB = 13.5 mm and CA = 3.2 mm. Find the length of BC, giving your answer rounded
adelina 88 [10]

Answer:

13.9

Step-by-step explanation:

Use Pythagorean Theorem:

Both of the lengths given are the legs,

13.5^2 + 3.2^2 = c^2

182.25 + 10.24 = c^2

192.49 = c^2

13.87 = c

8 0
3 years ago
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