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3 years ago

The domain for f(x) is all real numbers greater than or equal to ___ ?

Mathematics

2 answers:

Shkiper50 [21]3 years ago

7 0

You must set each part of the function equal to zero.

5√(x+2) = x is greater than or equal to -2

So the domain is greater than or equal to -2

g100num [7]3 years ago

7 0

Answer:

The domain of f(x) is all real numbers greater than or equal to -2

Step-by-step explanation:

We have been given that

$f(x)=2(x)^2+5\sqrt{x+2}$

Domain is the set of x values for which the function is defined.

The given function is the combination of a square and square root function.

Square function is defined for all real values. Whereas, the square root function is defined for only positive values.

Therefore, the function is defined when

$x + 2\geq0$

Subtract 2 to both sides

$x\geq-2$

Hence, the domain of f(x) is all real numbers greater than or equal to -2

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PLEASE HELP ASAP!!!

EleoNora [17]

Part 1:

$(x+1)^2-3(x+2) \\ \\ =x^2+2x+1-3x-6 \\ \\ =x^2-x-5$

option b.

Part 2:
$(5x^3y^{-3})(-6x^4y)\\ \\=5(-6)x^{3+4}y^{-3+1}\\ \\=-30x^7y^{-2}\\ \\=\frac{-30x^7}{y^2}$

option d

Part 3:
$\frac{8+x}{2} - \frac{x+3}{3} =4$

Multiply through by the LCM of 2 and 3 (i.e. 6)
$6\left(\frac{8+x}{2}\right) - 6\left(\frac{x+3}{3}\right) =6(4) \\ \\ 3(8+x)-2(x+3)=24 \\ \\ 24+3x-2x-6=24 \\ \\ x+18=24 \\ \\ x=24-18=6$

option b

Part 4
x^2-3x-8=x+4

$x^2-3x-8=x+4 \\ \\ x^2-3x-x-8-4=0 \\ \\ x^2-4x-12=0 \\ \\ (x-6)(x+2)=0 \\ \\ x=6 \ or \ -2$

option d

Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?

In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.

Therefore, he should add 16 to both sides because (8/2)^2=16.

option d.

5 0

3 years ago

Help thank you! loll

snow_tiger [21]

Answer:

I think the answer is A.

But I am not sure.

3 0

2 years ago

35 Points!!

nexus9112 [7]

Answer:

- Equal midpoints of AC and BC.

- The product of the slopes of the diagonals AC and DB is -1.

Step-by-step explanation:

1. Plot the given points, as you can see in the graph attached.

2. Calculate the midpoint of AC and DB:

$M_{AC}=(\frac{-5+(-1)}{2},\frac{-1+5}{2})=(-3,2)\\M_{DB}=(\frac{-9+3}{2},\frac{6+(-2)}{2})=(-3,2)$

Therefore, the midpoint of AC and DB are equal.

3. Calculte the slope of the diagonals AC and DB:

$m_{AC}=\frac{5-(-1)}{-1-(-5)}=\frac{3}{2}\\m_{DB}=\frac{-2-6)}{3-(-9)}=-\frac{2}{3}$

4. Multiply the slopes of the diagonals:

$(\frac{3}{2})(-\frac{2}{3})=-1$ (AC and DB are perpendicular)

5 0

3 years ago

Changethe improper fraction into an equal mixed number 15/4

frez [133]

Answer:

15 divided by 4 = 3 3/4

Step-by-step explanation:

First divide 15 on 4 to get 3.75. convert 3.75 to a fraction. 3 will stay as three, and 0.75 will be converted to 3/4. the answer to your question is 3 and 3/4. I hope this was correct. if it was then please mark as brainliest.

3 0

3 years ago

Read 2 more answers

-q2 - r2+ 3s if q = 9, r = -6, s = -20 how do I solve this?

ANEK [815]

Step-by-step explanation:

-9(2)-(-6)(2)+3(-20)

(−9)(2)−(−6)(2)+(3)(−20)

=−18−(−6)(2)+(3)(−20)

=−18−(−12)+(3)(−20)

=−6+(3)(−20)

=−6+−60

=−66

6 0

3 years ago