Is (8,8) a solution to the equation y=x?
2 answers:
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4.
known side: opposite (150m)
unknown sides: adjacent and hypotenuse
using Tan to find the distance from the tower's base to the key.
why do we use Tan to find the distance?
the tower creates an angle of 72 degrees with the ground, which will be called α, and it is 150m high from the ground which is opposite ∠α. (shown in picture). we can see that the distance from the base of the tower to the key is the adjacent of the ∠α.
Tan α = opposite / adjacent
=> Tan 72° = 150 / x
=> x = 150 / Tan 72°
=> x = 48.73795443 m = ~48.7m
5.
4.
known side: opposite (150m)
unknown sides: adjacent and hypotenuse
using Sin to find the distance that the ant travelled.
why do we use Sinn to find the distance?
the tower creates an angle of 72 degrees with the ground, which will be called α, and it is 150m high from the ground which is opposite ∠α. (shown in picture). the ant travelled along the tower's body, which is the hypotenuse of the triangle, from the top until reaching the ground.
Sin α = opposite / hypotenuse
=> Sin 72° = 150 / x
=> x = 150 / Sin 72°
=> x = 157.7193336 m = ~157.7m
6.
(using unrounded numbers to calculate because there is a small difference in results if using the rounded numbers)
c^2 = a^2 + b^2 (pythago)
157.7^2 = 150^2 + 48.7^2
24875.3882 = 24875.3882 (correct)
1. when you see 4(x² - 1), then you have to multiply 4 with everything in the bracket. keep in mind that you always have to be cautious of the sign whether it is a positive or a negative.
positive ×/÷ positive = positive
negative ×/÷ negative = positive
positive ×/÷ negative = negative
negative ×/÷ positive = negative
^ you have to remember this.
2. only like terms (same alphabet) can plus or minus each other.
3. simplify by taking out the common factor and placing it outside the bracket.
positive ×/÷ positive = positive
negative ×/÷ negative = positive
positive ×/÷ negative = negative
negative ×/÷ positive = negative
^ you have to remember this.
2. only like terms (same alphabet) can plus or minus each other.
3. simplify by taking out the common factor and placing it outside the bracket.