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3 years ago

A tidal power plant relies on a dam built ? From a beach into the sun

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

7 0

Ok no It doesn’t be a little more specific please

Step2247 [10]3 years ago

4 0

Answer:

across a bay or estuary

Step-by-step explanation:

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Julia is five years older than her sister Babs, and their ages add up to 31. How old is Babs?

Tresset [83]

<span>Julia is X+5

</span><span>x+x+5=31
</span>
Now we just solve the equation

2x=31-5
x=26/2
x=13 years old (Babs' age)

and we know that julia is 5 years older this gives us the conclusion that.

13+18=31

4 0

3 years ago

Read 2 more answers

Can someone help me on this too!

Ann [662]

Answer:

72 signs

Step-by-step explanation:

90 min = 1.5 hour

6 hours hangs 6/1.5 * 18 signs = 72

3 0

3 years ago

Read 2 more answers

Express 2x^2+8x+3 in the form 2(x+p)^2+q

e-lub [12.9K]

Answer:

2(x + 2)² - 5

Step-by-step explanation:

Given

2x² + 8x + 3

To obtain the required form use the method of completing the square.

The coefficient of the x² term must be 1, thus factor 2 out of 2x² + 8x

= 2(x² + 4x) + 3

add/subtract ( half the coefficient of the x- term)² to x² + 4x

= 2(x² + 2(2)x + 4 - 4) + 3

= 2(x + 2)² - 8 + 3

= 2(x + 2)² - 5

with p = 2 and q = - 5

4 0

3 years ago

Eli wants to combine 0.5 gallon of a 10% acid solution with some 35% acid solution to make a 15% acid solution. How much of the

emmainna [20.7K]

Answer:

<h3> 0.125 galon of 35% acid solution</h3>

Step-by-step explanation:

0.5 gallon of a 10% acid solution

10%•0.5 = 0.05 gallon of acid in that solution

x gallon of 35% acid solution

35%•x = 0.35x gallons of acid in that solution

0.05 + 0.35x total of gallons of acid in both solutions

(0.5+x) gallons of 15% acid solution

15%(0.5+x) = 0.15(0.5+x) gallons of acid in that solution

the amount of gallons of acid didn't change after mixing, so:

0.05 + 0.35x = 0.15(0.5 + x)

0.05 + 0.35x = 0.075 + 0.15x

0.35x - 0.15x = 0.075 - 0.05

0.2x = 0.025

×5 ×5

x = 0.125

8 0

3 years ago

Read 2 more answers

A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the

Kay [80]

Answer: The required number of quarters in the collection is 11.

Step-by-step explanation: Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05, 1 dime = $ 0.10 and 1 quarter = $0.25.

Then, according to the given information, we have

$x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

$(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)$

and

$y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Comparing the values of y from equations (iv) and (v), we get

$47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.$

Thus, the required number of quarters in the collection is 11.

7 0

3 years ago