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liq [111]
2 years ago
6

What is the opposite of 45? if I get a good answer i would appreciate it very much!

Mathematics
1 answer:
Lapatulllka [165]2 years ago
7 0

Answer:

-45

Step-by-step explanation:

The opposite of a number has the same value, but a different sign

Adding them will result in 0

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If an employer reduces the working week from 40 hours to 35 hours, with no
tangare [24]

Answer:

14.285714285714 %

Step-by-step explanation:

suppose the weekly payment is of x dollars

Then

Previous payment : $(x/40) per hour

New payment : $(x/35) per hour

Then

The percentage increase in the hourly rate of pay is :

=\frac{\frac{x}{35} -\frac{x}{40} }{\frac{x}{40} } \times100

=\frac{\frac{5x}{1400} }{\frac{x}{40} }  \times100

=\frac{5x}{1400} \times \frac{40}{x} \times100

=\frac{200}{1400} \times100

=\frac{1}{7} \times100

=14.285714285714

6 0
2 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
Hey guys please help
omeli [17]
True.
Angle c=anglez
Angle RHC=angle XHZ
Therefore they’re similar.
Pls mark me as the Brainliest as I really need it, thanks!
7 0
2 years ago
write an equation of a line that passed through the point (2,0) and is a perpendicular to the line y=-1.5+3
kotegsom [21]

You will be using the equation y = mx + b

The only variables you need to find are "m" and "b"

For the equation of a line to be perpendicular to the given line, the slope will have to be the opposite of the given slope. Or you have to flip the sign and the number of the given slope to get your new slope.

For example:

m = -2

perpendicular slope = 1/2(positive)

m = 3/4

perpendicular slope = -4/3(negative)


The slope of the line is -1.5 or -3/2

Your new slope is 2/3

y = 2/3x + b

To find "b", you plug in the point (2,0) into the equation.

0 = 2/3(2) + b

0 = 4/3 + b

-4/3 = b


Your new equation is y = 2/3x - 4/3

7 0
3 years ago
A members-only speaker series allows people to join for $20 and then pay $1 for every
Paha777 [63]

Answer:

30

Step-by-step explanation:

3 0
2 years ago
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