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Akimi4 [234]
3 years ago
8

Create a system of linear equations that has one solution of y=2x+1 and y=2x+2

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0

y = 2x + 1 \\  \\ 1. \: y - 1 = 2x \\  \\ 2. \:  \frac{y - 1}{2}  = x \\  \\ 3. \: x =  \frac{y - 1}{2} \\  \\  \\ y = 2x + 2 \\  \\ 1. \: y - 2 = 2x \\  \\ 2. \:  \frac{y - 2}{2} = x \\  \\ 3. \:  - 1 +  \frac{y}{2}  = x \\  \\ 4. \:  \frac{y}{2}  - 1 = x \\  \\ 5. \: x =  \frac{y}{2}  - 1

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Kate and Jean paint a house together in 6 days. If they work alone, Kate takes 5 fewer days than Jean would take to do the same
ELEN [110]
Katework+jeanwork=6
work alone
Katework=-5+Jeanwork
ad 5 to both sides
Katework+5=jeanwork
subsitute 5+katework for jeanwork
5+katework+kateworkwork=6
subtract 5 from both sides
2katework=1
divide both sides by 2
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equation would be
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5 0
3 years ago
X-2y = 3<br> 2x + y = 11<br> What is the value of x
mrs_skeptik [129]

Answer:

x=5 y=1

Step-by-step explanation:

4 0
2 years ago
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A rectangle tank is 21cm long,13 cm wide and 18cm high and contains water up to a height of 11cm theb the volume of water in lit
Zolol [24]

Answer:

3003 cm³

Step-by-step explanation:

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6 0
2 years ago
Can some one help me please fast
frez [133]
10.
1/2 and 3/5 have the denominators 2 and 5. The smallest number that both 2 and 5 can go into is 10.
4 0
3 years ago
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Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce
34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)

= 1 - P(z \leq -2)

Calculation the value from standard normal z table, we have,  

P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < 23.7) =0.159= 15.9\%

15.9% of of the boxes weigh less than 23.7 ounces.

7 0
3 years ago
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