All categories

2 years ago

What is the equation of the given line?

Mathematics

2 answers:

Sergeu [11.5K]2 years ago

8 0

Answer:

2,2gggffgigzrfgcf gg cyg

Vladimir79 [104]2 years ago

4 0

Answer:

y=0x+5

Step-by-step explanation:

You might be interested in

How can you show your work for 8800 divided by 4

irakobra [83]

The number 8800 is called the numerator or dividend, and the number 4 is called the denominator or divisor.

The quotient of 8800 and 4, the ratio of 8800 and 4, as well as the fraction of 8800 and 4 all mean (almost) the same:

8800 divided by 4, often written as 8800/4.

Read on to find the result of 8800 divided by 4 in decimal notation, along with its properties.

What is 8800 Divided by 4?
We provide you with the result of the division 8800 by 4 straightaway:

8800 divided by 4 = 2200

The result of 8800/4 is an integer, which is a number that can be written without decimal places.
8800 divided by 4 in decimal = 2200
8800 divided by 4 in fraction = 8800/4
8800 divided by 4 in percentage = 220000%
Note that you may use our state-of-the-art calculator above to obtain the quotient of any two integers or decimals, including 8800 and 4, of course.

7 0

2 years ago

5/8 of the cats perferred drinking with there tongue but 3/16 wanted a straw if there was 39 cats that gave one of these 2 answe

AveGali [126]

Answer:

208cats

Step-by-step explanation:

⅝=tongue

³/16=straw=39cats

⅝+³/16=13/16

meaning total number of cats is 16/16

If ³/16=39cats

16/16=?

39×16/3

=208cats

6 0

3 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

Help me please, it would be great

Nastasia [14]

AB²=5²+5²+5²=25+25+25=75
AB=5√3≈8.7
Answer:AB≈8.7

4 0

3 years ago

Last year, Bob used 10 bottles of shampoo and 8 bottles of conditioner. His sister, Kayla, used 7 bottles of shampoo and 6 bottl

REY [17]

The lower ratio would be bob and that dude need to slow down the hair stuff

10 to 8 ratio is about 8.00
7 to 6 ratio is about 9.00

im not to good at math so dubble cheek just in case hope i could help tho

rip my spelling

6 0

3 years ago