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2 years ago

4e^2x-6=10

e" class="latex-formula">

Mathematics

2 answers:

Aloiza [94]2 years ago

5 0

Answer:

x= 4/e^2

alternate form 0.541341

Step-by-step explanation:

Taya2010 [7]2 years ago

3 0

X=4/e^2 or X=0.541341

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I need help for Part A and B

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Step-by-step explanation:

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3 years ago

1. Name the congruent segments in this figure.

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Answer: of what figure

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3 years ago

A litre bottle of KERPOW washing up liquid costs £1.95.

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Answer:

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Step-by-step explanation:

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2 years ago

The function f(x) = x2 is graphed on a coordinate grid. Lauren wants to graph g(x) = (x + 2)2 + 3 on the same grid. Which of the

PSYCHO15rus [73]

Answer:

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Step-by-step explanation:

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3 years ago

A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the

nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

$\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1$

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

$\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1$

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

$\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883$

So, the horizontal distance from the center is 49.3883 feet

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3 years ago