Answer:

If you compare this to
, then
and
.
Step-by-step explanation:
We are given
and we are asked to find the value of
.
So we will need to find
.

Square both sides:

Expand using identity:
.



Let's go back to the full
.




If you compare this to
, then
and
.
Answer:
+ 9x + 8 = 0
Step-by-step explanation:
First, we have to simplify this quadratic equation:
(x+2)^2 + 5(x+2) - 6 = 0
x^2 + 4x + 4 + 5x + 10 - 6 = 0
x^2 + 9x + 8 = 0
4c+3=15
You need to get rid of the 3
So you minus it from each side so you
4c=12
12/4=3
So c =3
Answer:
63
Step-by-step explanation:
yan po sagot ko Hindi ko po alam kung tama o Hindi basta yan po sagot ko...
Answer:x=-20
Step-by-step explanation: