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Paraphin [41]
3 years ago
5

Use the "rule of 72" to estimate the doubling time (in years) for the interest rate, and then calculate it exactly. (Round your

answers to two decimal places.) 7.7% compounded weekly.
"rule of 72" yr

exact answer yr
Mathematics
1 answer:
bonufazy [111]3 years ago
6 0

Answer:

Using the rule of 72, the doubling time is 9.35 years.

The exact answer is that the doubling time is 8.89 years.

Step-by-step explanation:

By the rule of 72, we have that the doubling time D is given by:

D = \frac{72}{Interest Rate}

The interest rate is in %.

In our exercise, the interest rate is 7.7%. So, by the rule of 72:

D = \frac{72}{7.7} = 9.35.

Exact answer:

The exact answer is going to be found using the compound interest formula(since the rule of 72 is a simplification of this formula).

The compound interest formula is given by:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

So, for this exercise, we have:

We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.

A = 2P

r = 0.077

There are 52 weeks in a year, so n = 52

A = P(1 + \frac{r}{n})^{nt}

2P = P(1 + \frac{0.077}{52})^{52t}

2 = (1.0015)^{52t}

Now, we apply the following log propriety:

\log_{a} a^{n} = n

So:

\log_{1.0015}(1.0015)^{52t} = \log_{1.0015} 2

52t = 462.44

t = \frac{462.44}{52}

t = 8.89

The exact answer is that the doubling time is 8.89 years.

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Use the intermediate value theorem to find the value of c such that f(c) = M. f(x) = x^2 - x + 1 text( on ) [1,8]; M = 21 c =
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Answer:

c = 5

Step-by-step explanation:

Given

f(c) = M

f(x) = x^2 - x + 1

Interval: [1,8]

M = 21

Required

Find c using Intermediate Value theorem

First, check if the value of M is within the given range:

f(x) = x^2 - x + 1

f(1) = 1^2 - 1 + 1

f(1) = 1

f(x) = 8^2 - 8 + 1

f(x) = 57

1 \le M \le 57

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M is within range.

Solving further:

We have:

f(c) = f(x) = M

f(x) = 21

Substitute 21 for f(x) in f(x) = x^2 - x + 1

21 = x^2 - x + 1

Express as quadratic function

x^2 - x + 1 - 21  = 0

x^2 - x - 20  = 0

Expand

x^2 + 4x - 5x - 20

x(x+4)-5(x+4)=0

(x - 5)(x+4) = 0

x - 5 = 0 or x + 4= 0

x = 5 or x = -4

The value of x = -4 is outside the Interval: [1,8]

So:

x = 5

f(c) = f(x) = M

f(c) = f(5) = 21

By comparison:

c = 5

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For each pair of expressions below, without substituting in specific values, determine which of the expressions in the given pai
miv72 [106K]

Answer:

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  2. 15/x²
  3. it depends (see below)
  4. it depends (see below)

Step-by-step explanation:

1. t² is a positive number. Adding a positive number to 5 will always produce a larger result than subtracting the same positive number from 3. The larger expression is 5+t².

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2. The expressions are only defined for x ≠ 0, so for x² a positive number. For any x, the expressions are both positive. 15/(7x²) is 1/7 of 15/x², so will always be smaller. The larger expression is 15/x².

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3. As in 2, these expressions are only defined for x ≠ 0. One expression is the opposite of the other. A number is greater than its opposite when it is positive, so 1/x > 1/-x for x > 0; and 1/-x > 1/x for x < 0.

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4. The expression (k -6)² has the same range of values as k², but its graph is shifted 6 units to the right. The left branch of (k -6)² will be greater than k² for any k < 3. Similarly, the right branch of k² will be greater than (k -6)² for any k > 3.

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