Answer:
Using the rule of 72, the doubling time is 9.35 years.
The exact answer is that the doubling time is 8.89 years.
Step-by-step explanation:
By the rule of 72, we have that the doubling time D is given by:
![D = \frac{72}{Interest Rate}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B72%7D%7BInterest%20Rate%7D)
The interest rate is in %.
In our exercise, the interest rate is 7.7%. So, by the rule of 72:
.
Exact answer:
The exact answer is going to be found using the compound interest formula(since the rule of 72 is a simplification of this formula).
The compound interest formula is given by:
![A = P(1 + \frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%20%3D%20P%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.
So, for this exercise, we have:
We want to find the doubling time, that is, the time in which the amount is double the initial amount, double the principal.
![A = 2P](https://tex.z-dn.net/?f=A%20%3D%202P)
![r = 0.077](https://tex.z-dn.net/?f=r%20%3D%200.077)
There are 52 weeks in a year, so ![n = 52](https://tex.z-dn.net/?f=n%20%3D%2052)
![A = P(1 + \frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%20%3D%20P%281%20%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
![2P = P(1 + \frac{0.077}{52})^{52t}](https://tex.z-dn.net/?f=2P%20%3D%20P%281%20%2B%20%5Cfrac%7B0.077%7D%7B52%7D%29%5E%7B52t%7D)
![2 = (1.0015)^{52t}](https://tex.z-dn.net/?f=2%20%3D%20%281.0015%29%5E%7B52t%7D)
Now, we apply the following log propriety:
![\log_{a} a^{n} = n](https://tex.z-dn.net/?f=%5Clog_%7Ba%7D%20a%5E%7Bn%7D%20%3D%20n)
So:
![\log_{1.0015}(1.0015)^{52t} = \log_{1.0015} 2](https://tex.z-dn.net/?f=%5Clog_%7B1.0015%7D%281.0015%29%5E%7B52t%7D%20%3D%20%5Clog_%7B1.0015%7D%202)
![52t = 462.44](https://tex.z-dn.net/?f=52t%20%3D%20462.44)
![t = \frac{462.44}{52}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B462.44%7D%7B52%7D)
![t = 8.89](https://tex.z-dn.net/?f=t%20%3D%208.89)
The exact answer is that the doubling time is 8.89 years.