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Sophie [7]
3 years ago
12

Rex drove 258.5 miles in 5.5 hours. what is his average rate of speed?

Mathematics
1 answer:
marta [7]3 years ago
3 0

answer:

47

Step-by-step explanation:

258.5/5.5=47

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What is 13/15÷5 3/4 ​
Nataliya [291]

Answer:

52/345

Step-by-step explanation:

3 0
2 years ago
If you could help me that would be amazing!!
earnstyle [38]
The answer is C

Please mark as a brainliest above my comment
6 0
2 years ago
CAN SOMEONE HELP PLEASE <br> m4A=42°, b=10, c= 12. What is the length of a to the nearest tenth?
kipiarov [429]

<u>Answer:</u>

a = 8.1

<u>Step-by-step explanation:</u>

Use the cosine rule:

a = \sqrt{b^2 + c^2 -2 bc \space\ cosA }

Substituting the values:

a = \sqrt{10^2 + 12^2 -2(10)(12) \space\ cos 42 \textdegree\ }

⇒ a = \sqrt{4 \space\ cos 42\textdegree\ }

⇒ a = 8.1

4 0
2 years ago
HELP! Find the value of the 30th percentile of the following set of data. 129, 113, 200, 100, 105, 132, 100, 176, 146, 152
BlackZzzverrR [31]
Let list the data in ascending order 100, 100, 105, 113, 129, 132, 146, 152, 176, 200

There are ten numbers so the thirtieth percentile would be the .3 * 10 

= 3rd number, ordered from smallest to largest. 

so the third number, the thirtieth percentile, is 105

7 0
3 years ago
Genetic Inheritance: Calculate probability of two children having the same genotype for achrondoplasia Achondroplasia is a commo
dimaraw [331]

Answer:

The correct answer is - 1/2 or 50% for first and second child to be affected.

Step-by-step explanation:

Achondroplasia is an autosomal dominant disorder. Autosomal dominant disorder refers to the presence of a single copy of the defective gene that is enough to lead to dwarfness.

A cross of achondroplasia (Aa) parent to a person of normal height (aa) result in half of their children will be affected with dwarfism and the other half will be normal.

a  cross between affected or dwarf  and normal parent

     Aa X aa

Punnett square:

         a a

A  Aa Aa

a aa aa

Aa- dwarfness

aa- normal height

The probability that both their first child and second child would have achondroplasia is

2/4 =1/2 or 50%.

6 0
3 years ago
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