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miskamm [114]
3 years ago
13

Find the area of the large rectangle by finding the area of the two small rectangles and adding them.

Mathematics
2 answers:
ASHA 777 [7]3 years ago
5 0

Answer:

Area of the given figure is 21 square units

Step-by-step explanation:

Area of the rectangle formula is length times width

Area of the top rectangle  

Length = 5 and width = 3

So area of top rectangle =5 times 3 is 15 square units

Area of bottom rectangle  

length =2 and width =3

So area of bottom rectangle is 2 times 3 is 6 square units

Total area =15+6= 21 square units

jekas [21]3 years ago
4 0

The total area is 21 (15+6=21)

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Answer:

D. length = 10 cm; width = 7 cm

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ladessa [460]

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Step-by-step explanation:

7 0
2 years ago
Foci of ellipse of 3x2 + y2 =9
Oksi-84 [34.3K]

Answer:

x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3

Step-by-step explanation:

Let's solve for x.

3x2+y2=9

Step 1: Add -y^2 to both sides.

3x2+y2+−y2=9+−y2

3x2=−y2+9

Step 2: Divide both sides by 3.

3x^2/3= -y^2+9/3

x^2=-1/3 y^2 +3

x=√-1/3 y^2 +3 or x=-√-1/3 y^2 +3

Hope it helped!

8 0
3 years ago
How can i do this please help me
Aleksandr-060686 [28]

The tangent of an angle is the ratio of the opposite side to the adjacent side.

... tan(45°) = (height above eye level)/(20 m)

... height above eye level = (20 m)·tan(45°) = (20 m)·1 = 20 m

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Eye level is 1.7 m above ground, so the height of the flagpole above ground is

... height of pole = height above eye level + height of eye level

... height of pole = 20 m + 1.7 m = 21.7 m

7 0
3 years ago
When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra
Sergeu [11.5K]

Answer:

r=\sqrt{10}\text{ m}

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

V=\pi r^2h, where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be h = 0.7 meters at V=22\text{ m}^3.

Upon substituting these values in above formula, we will get:

22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})

22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}

\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2

r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}

r^2=10\text{ m}^2

Now, we will take positive square root of both sides as radius cannot be negative.

\sqrt{r^2}=\sqrt{10\text{ m}^2}

r=\sqrt{10}\text{ m}

Therefore, radius of tank would be approximately square root of 10 m.

5 0
3 years ago
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