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3 years ago

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Explain whether nitrogen atoms will form bonds with other atoms

1 answer:

iren2701 [21]3 years ago

3 0

The closer the atoms are the more the nitrogen will be come bigger or the oppisite

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What is related to the energy of motion of the particles of matter?

Amanda [17]

The Kinitec Molecular Theory of Matter
Yes Kninetic energy

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4 years ago

An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f

Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

Mass of carbon, $C$ :

$\frac{32.18}{100}\times 223.94 = 72.06 g$

Mass of hydrogen, $H$ :

$\frac{4.5}{100}\times 223.94 = 10.08 g$

Mass of chlorine, $Cl$ :

$\frac{63.32}{100}\times 223.94 = 141.79 g$

Now, the number of each element in the unknown compound is determined by the formula:

$number of moles = \frac{given mass}{molar mass}$

Number of moles of $C$ :

$number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole$

Number of moles of $H$ :

$number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole$

Number of moles of $Cl$

$number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole$

Dividing each mole with the smallest number of mole, to determine the empirical formula:

$C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}$

$C_{1.5}H_{2.5}Cl_{1}$

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is $C_{3}H_{5}Cl_{2}$ .

Empirical mass = $12\times 3+1\times 5+2\times 35.5 = 112 g/mol$

In order to determine the molecular formula:

n = $\frac{molar mass}{empirical mass}$

n = $\frac{223.94}{112} = 1.99 \simeq 2$

So, the molecular formula is:

$2\times C_{3}H_{5}Cl_{2} = C_{6}H_{10}Cl_{4}$

6 0

3 years ago

Consider the balanced equation of K I KI reacting with P b ( N O 3 ) 2 Pb(NOX3)X2 to form a precipitate. 2 K I ( a q ) + P b ( N

professor190 [17]

Answer: 50.7 grams

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

a) moles of $KI$

$\text{Number of moles}=molarity\times {\text {Volume in L]}=0.417M\times 0.528L=0.220moles$

The balanced chemical equation is:

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)$

$KI$ is the limiting reagent as it limits the formation of product and $Pb(NO_3)_2$ is in excess.

According to stoichiometry :

2 moles of $KI$ give = 1 mole of $PbI_2$

Thus 0.220 moles of $KI$ give= $\frac{1}{2}\times 0.220=0.110moles$ of $PbI_2$

Mass of $PbI_2=moles\times {\text {Molar mass}}=0.110moles\times 461.01g/mol=50.7g$

Thus 50.7 g of $PbI_2$ will be formed.

6 0

4 years ago

ludmilkaskok [199]

Answer: The molecular formula will be $C_3H_9$

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula is $CH_3$

The empirical weight of $CH_3$ = 1(12)+3(1)= 15g.

The molecular weight = 45.0 g/mole

Now we have to calculate the molecular formula:

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{45}{15}=3$

The molecular formula will be= $3\times CH_3=C_3H_9$

Thus molecular formula will be $C_3H_9$

6 0

3 years ago

Sam and Jane have been investigating the amount of copper sulphate that can be dissolved in water at different temperatures .The

MAXImum [283]

Answer:

This question is so confusing, I'm sorry

8 0

3 years ago