On a distance vs time graph the line of an object at rest is a

1 answer:

3 0

A point. A line would show progressing distance over passing time. Since the object is not going anywhere it would just be a point. I would also assume that this point would be sitting at the 0 on the distance axis. (this assumes Distance is the x axis)

If the x-axis is time and the y-axis is distance you will get a horizontal line because time will be passing but the distance will (Y value) constant (at rest).

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A mixture of gaseous CO and H2, called synthesis gas, is used commercially to prepare methanol (CH3OH), a compound considered an

mr_godi [17]

Answer : The value of equilibrium constant (K) is, 424.3

Explanation : Given,

Concentration of $H_2$ at equilibrium = 0.067 mol

Concentration of $CO$ at equilibrium = 0.021 mol

Concentration of $CH_3OH$ at equilibrium = 0.040 mol

The given chemical reaction is:

$CO+2H_2\rightarrow CH_3OH$

The expression for equilibrium constant is:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the given values in this expression, we get:

$K_c=\frac{(0.040)}{(0.021)\times (0.067)^2}$

$K_c=424.3$

Thus, the value of equilibrium constant (K) is, 424.3

4 0

3 years ago

Find [cu2+] in a solution saturated with cu4(oh)6(so4) if [oh − ] is fixed at 2.3 ✕ 10−6 m. note that cu4(oh)6(so4) gives 1 mol

ki77a [65]

<span>

</span> $Cu_4(OH)_6(SO_4)$
<span>
You have OH- conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is 4 : 6 = 2:3

So, for 2.3 ✕ 10−6 m OH-
[Cu2+] = $\frac{2}{3} \times 2.3 \times 10^{-6}$

$= 1.53 \times 10^{-6} 
$

6 0

3 years ago

Mg+o2 balanced eaquation

Tanya [424]

Answer:

2Mg+O2=2MgO

balanced equation

hope it helps.

5 0

3 years ago

Read 2 more answers

A Balanced Equation: The total amount of atoms involved in the chemical reaction changes depending on the reaction. True or fals