A student successfully neutralizes 25.0mL of HCl(aq) during a titration experiment with 18.5mL of 0.150M NaOH(aq). What is the c
1 answer:
Answer:
The concentration is 0.111 M.
Explanation:
Use dimensional analysis to solve the problem. Since both HCl and NaOH are strong, the dissociate completely in solution.
For this neutralization, the reaction is HCl + NaOH = NaCl + HOH
18.5 mL x x
x
= 0.002775 moles HCl
Molarity = moles/ Liters
Molarity of HCl = 0.002775 moles HCl / 0.025 L = 0.111 M
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