Question

A student successfully neutralizes 25.0mL of HCl(aq) during a titration experiment with 18.5mL of 0.150M NaOH(aq). What is the concentration of the HCl(aq)?

Answer 1

Answer:

The concentration is 0.111 M.

Explanation:

Use dimensional analysis to solve the problem. Since both HCl and NaOH are strong, the dissociate completely in solution.

For this neutralization, the reaction is HCl + NaOH = NaCl + HOH

18.5 mL x $\frac{1 L}{1000 mL}$ x $\frac{0.150 moles NaOH}{1 L}$ x $\frac{1 mole HCl}{1 mole NaOH}$ = 0.002775 moles HCl

Molarity = moles/ Liters

Molarity of HCl = 0.002775 moles HCl / 0.025 L = 0.111 M