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My name is Ann [436]
3 years ago
9

A student successfully neutralizes 25.0mL of HCl(aq) during a titration experiment with 18.5mL of 0.150M NaOH(aq). What is the c

oncentration of the HCl(aq)?
Chemistry
1 answer:
son4ous [18]3 years ago
5 0

Answer:

The concentration is 0.111 M.

Explanation:

Use dimensional analysis to solve the problem. Since both HCl and NaOH are strong, the dissociate completely in solution.

For this neutralization, the reaction is HCl + NaOH = NaCl + HOH

18.5 mL x \frac{1 L}{1000 mL} x \frac{0.150 moles NaOH}{1 L} x \frac{1 mole HCl}{1 mole NaOH} = 0.002775 moles HCl

Molarity = moles/ Liters

Molarity of HCl = 0.002775 moles HCl / 0.025 L = 0.111 M

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balandron [24]

Explanation:

mass H2O2 = 55 mL(1.407 g/mL) = 80.85 g

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moles H2O2 = 80.85 g/34.02 g/mol = 2.377 moles H2O2

For each mole of H2O2 you obtain 0.5 mole of O2 (see the equation).

moles O2 = 2.377 moles H2O2 (1 mole O2)/(2 moles H2O2) = 1.188 moles O2

Now, you need the temperature.  If you are at STP (273 K, and 1.00 atm) then 1 mole of an ideal gas at STP has a volume of 22.4 L.  Without temperature you are not really able to continue.  I will assume you are at STP.

Volume O2 = 1.188 moles O2(22.4 L/mole) = 0.0530 L of O2.

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svetlana [45]
I will assume that the sign ? between the C and the CCH3 is a triple bond, and I will represent it by three vertical lines |||


So the reaction is:


<span>CH3CH2CH2CH2C ||| CCH3+2Br2 ---->


This is a typical reaction known as halogenation of alkines.


This is an addition reaction, i.e. the alkyne undergoes an addition of the Br2 (and it also happens with Cl2) to the triple bond to form a tetra halide.


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</span>                                                                                                        |     |
<span><span>CH3CH2CH2CH2C ||| CCH3+2Br2 ---->  CH3 CH2 CH2 CH2 C - C</span> - CH3
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</span>
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Answer:qui

qzasui

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