Answer:So, since it is continuously, we need to think of PERT
A=P\times e^{rt}
So, we just plug our numbers in to solve for T
8000=4000e^{.07t}\\\ln(8000)=\ln(4000e^{.07t})\\\ln(8000) = \ln(4000) + \ln(e^{.07t})\\\ln(8000)=\ln(4000)+.07t\ln(e)\\\ln(8000)=\ln(4000)+.07t\\\frac{\ln(8000)}{\ln(4000)}=.07t\\\frac{\ln(8000)}{.07\ln(4000)}=t\\ 15.479=t
It will take 15.479 years
Step-by-step explanation:
Answer:
C. Y=1,200(1-0.035)x
Step-by-step explanation:
Answer:
(x + 9)(5x - 1)
Step-by-step explanation:
Given
5x² + 44x - 9
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 5 × - 9 = - 45 and sum = + 44
The factors are + 45 and - 1
Use these factors to split the x- term
5x² + 45x - x - 9 ( factor the first/second and third/fourth terms )
= 5x(x + 9) - 1(x + 9) ← factor out (x + 9) from each term
= (x + 9)(5x - 1) ← in factored form
Answer:
314.16
Step-by-step explanation:
Area=πr2
d=2r
Solving for Area
A=1
4πd2=1
4·π·202≈314.15927
Answer:
Step-by-step explanation:
if m and n are irrational number then the product of mn sometimes rational and sometime irrational
ex: √5 *√2=√10 irrational
ex: √8*√2=√16=4 rational
b-y=|x|+3
explain why |x|+3≥|x+3|
absolute value of any number is always positive
x |x|+3 ≥ |x+3|
1 4 = 4 in this case equal
2 5 5
-2 5 ≥ 1 in this case |x|+3≥|x+3|
in case of negative value of x then |x|+3>|x+3|
