Answer:
slope of EF=
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
∠SUT=21°
Step-by-step explanation:
two line are perpendicular to each other if product of their slope equal to -1
=-1
slope of HE=
=-
slope of EF=
slope of EF=-1
=
slope of EF= answer
∠QSR=45°,
∠PTQ=90°
if RT=24
then SQ=48
square is always a rectangle
given ∠SUT=3x+6
∠RUS=5x-4
∠SUT=∠RUS
3x+6=5x-4
x=5
∠SUT=3x+6=15+6=21°
∠SUT=21°
Answer:
x = 18
Step-by-step explanation:
8x = 12 * 12
8x = 144
x = 18
Ok so the first step to solve it is subtraction then it’s multiplication then additions
The answer
<span>the true answer is A) 4x^2+52x+165=320; x = 2.5
proof:
since </span><span>they want to limit its area to 320 in^2
x must be equal 2.5, because </span>4.(2.5)^2+52(2.5)+165= 25+130+165=320;
the main rule of the area of a triangle is
A= (base x height )/2
let be b the base and h the height
so h=20- 6b
so 50= b x( 20-6b) /2, implies 100/b = 20 - 6b
if b=x, we have 100= 20x -6x² this is equivalent to 6x² - 20x = -100
so the answer is
<span>D) None of the choices are correct.
</span>
<span>the largest dimensions that can be used for the fountain are
</span>
<span>B) x^2+8x+16=800
C) x^2+16=800
</span>
proof
x^2+8x+16=x^2+8x+4², 4² is the area of the square fountain, and x^2+8x should be the remaining of the area, t<span>he total space that the fountain and sidewalk can use is 800, it is less than 800 ft^2.
</span>Use the same method for. x^2+16=800
Answer:
(0,0)
Step-by-step explanation:
