Number line project

Solve for y 1/8y-2/3=5.5

amm1812

Answer:

y = 49 1/3

Step-by-step explanation:

1/8y-2/3=5.5

1/8y = 5.5 + 2/3

multiply both sides by 8:

y = 8(5.5 + 2/3) = 44 + 16/3 = 44 + 5 1/3 = 49 1/3

7 0

3 years ago

Read 2 more answers

One factor in rating a National Hockey League team is the mean weight of its players. A random sample of players from the Detroi

lukranit [14]

Answer:

1) Random: A random sample needs to be obtained in order to apply inference for the mean

2) Normality condition: The sampling distribution of $\bar X$ needs to be approximately normal. If we use a random sample size higher than 30 we can use the Central Limit theorem to verify this condition.

3) Independence: All the individual observations need to be independent. And we need to satisfy that our sample would be lower than 10% of the real population size.

Step-by-step explanation:

For this case we need three conditions:

1) Random: A random sample needs to be obtained in order to apply inference for the mean

2) Normality condition: The sampling distribution of $\bar X$ needs to be approximately normal. If we use a random sample size higher than 30 we can use the Central Limit theorem to verify this condition.

3) Independence: All the individual observations need to be independent. And we need to satisfy that our sample would be lower than 10% of the real population size.

Data given and notation

$\bar X=203$ represent the sample mean

$s=10.9$ represent the sample standard deviation

$n=17$ sample size

$\mu_o$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We can assume the following system of hypothesis.

Null hypothesis: $\mu = \mu_o$

Alternative hypothesis : $\mu\neq \mu_o$

The degrees of freedom on this case:

$df=n-1=10-1$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

7 0

3 years ago

NEED THIS DONE ASAP!! Thank you!!

g100num [7]

Answer:

$\overset{\frown}{WX}= 66^{\circ}$

Step-by-step explanation:

Inscribed Angle Theorem

The measure of an inscribed angle is half the measure of the intercepted arc.

First, use the Inscribed Angle Theorem to calculate the measure of arc WY.

$\displaystyle \angle WXY=\dfrac{1}{2} \overset{\frown}{WY}$

$\implies 57^{\circ}=\dfrac{1}{2} \overset{\frown}{WY}$

$\implies \overset{\frown}{WY}= 2 \cdot 57^{\circ}$

$\implies \overset{\frown}{WY}= 114^{\circ}$

Assuming XY is the diameter of the circle:

$\implies \overset{\frown}{WY}+ \overset{\frown}{WX}= 180^{\circ}$

$\implies 114^{\circ} + \overset{\frown}{WX}= 180^{\circ}$

$\implies \overset{\frown}{WX}= 180^{\circ} - 114^{\circ}$

$\implies \overset{\frown}{WX}= 66^{\circ}$

7 0

2 years ago

ten selected students took a. altitude test out of the total score of 100 these students scored 60,50,50,70,40,80,65,55,50 and 9

ira [324]

Answer:

• mean = 61

• mode = 50

• median = 57.5

Step-by-step explanation:

• The mean is calculated by adding all the values together, and dividing the result by the number of values.

∴ mean = $\frac{60 + 50 + 50 + 70 + 40 + 80 + 65 + 55 + 50 + 90}{10}$

⇒ mean = $\frac{610}{10}$

⇒ mean = 61

• The mode of a set of values is the value that is the most common (has highest frequency) among them.

50 is the most common value.

∴ mode = 50

• The median is the middle-value of a set of ordered values.

∴ We have to first rearrange the set:

⇒ 40, 50, 50, 50, 55, 60, 65, 70, 80, 90

Now we need to find the middlemost value:

Since we have 10 values, which is an even number, we have to use the formula:

median = $\frac{(n/2)^{th} \space\ term \space\ + \space\ [(n/2) + 1]^{th} \space\ term }{2}$

where n is the number of values.

∴ median = $\frac{(10/2)^{th} \space\ term \space\ + \space\ [(10/2) + 1]^{th} \space\ term }{2}$

⇒ median = $\frac{5^{th} \space\ term \space\ + \space\ 6^{th} \space\ term }{2}$

The 5th and 6th terms in our ordered series are 55 and 60 respectively.

∴ median = $\frac{55 + 60}{2}$

⇒ median = 57.5

5 0

2 years ago

Simplify the expression 144^1/2

WARRIOR [948]

I'm not sure if this is what you wanted, but I think that 144 to the power of 1/2 (.5) is 12.

8 0

3 years ago