The original is 5cm, the reduced is 2.5cm
2.5/5 = 0.5 = 1/2
Area is a square measurement, so the area of the reduced image would be the scale squared, which would be 1/2^2 which = 1/4
The answer is:
The area of the reduced design is 1/4 of the area of the original.
Is there any more information, such as the value of q? Otherwise the sum of q and 8 is q + 8 because "sum" indicates addition.
They are about 27 percent that are not seniors
Answer:
Step-by-step explanation:
Radius = r = 3 in.
Height = h = 2 in.
<u>Volume:</u>
![\sf Volume \ of \ the \ cylinder = \pi r^2 h\\\\V = (3.14)(3)^2(2)\\\\V =(3.14)(9)(2)\\\\V = (3.14)(18)\\\\V = 56.5 \ in.^3\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20Volume%20%5C%20of%20%5C%20the%20%5C%20cylinder%20%3D%20%5Cpi%20r%5E2%20h%5C%5C%5C%5CV%20%3D%20%283.14%29%283%29%5E2%282%29%5C%5C%5C%5CV%20%3D%283.14%29%289%29%282%29%5C%5C%5C%5CV%20%3D%20%283.14%29%2818%29%5C%5C%5C%5CV%20%3D%2056.5%20%5C%20in.%5E3%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
x = -12,
Step-by-step explanation:
-1 + 5/4x = -16
5/4 x = -16 + 1
5/4 x = -15
x = -15 * 4/5
x = -12.
