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umka21 [38]
3 years ago
14

Find the value of x for which ABCD must be a parallelogram.

Mathematics
1 answer:
Musya8 [376]3 years ago
5 0

The value of x is 13°.

Solution:

Given ABCD is a parallelogram.

⇒ AD || BC and AC is a transversal line.

<u>Property of parallel lines:</u>

<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>

∠DAC = ∠CAB

(4x - 1)° = (x + 38)°

4x° - 1° = x° + 38°

Add 1° on both sides.

4x° - 1° + 1° = x° + 38° + 1°

4x° = x° + 39°

Subtract x° from both sides.

4x° - x° = x° + 39° - x°

3x° = 39°

Divide by 3° on both sides.

x = 13°

The value of x is 13°.

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son4ous [18]

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3 years ago
A student pushes a 51.5 kilogram bookshelf across a smooth floor with a net force of 67 N.
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The acceleration of the bookshelf is equal to 1.30 m/s^2

<u>Given the following data:</u>

  • Mass of bookshelf = 51.5 kilogram
  • Net force = 67 Newton

To determine the acceleration of the bookshelf, we would apply Newton's Second Law of Motion:

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on the object while being inversely proportional to its mass.

Mathematically, Newton's Second Law of Motion is given by this formula;

Acceleration = \frac{Net\;force}{Mass}

Substituting the given parameters into the formula, we have;

Acceleration = \frac{67}{51.5}

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Read more on net force here: brainly.com/question/1121817

7 0
2 years ago
Rebecca draws a graph of a real world relationship that turns out to be a set of unconnected points . Can the relationship be li
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8 0
3 years ago
Find f'(x) and state the domain of f':<br> f(x) = In (2x^2+1)
-Dominant- [34]

Answer:

f'(x) = \frac{4x}{2x^2+1}

Domain: All Real Numbers

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Derivative: \frac{d}{dx} [ln(u)] = \frac{u'}{u}

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = ln(2x² + 1)

<u>Step 2: Differentiate</u>

  1. Derivative ln(u) [Chain Rule/Basic Power]:                          f'(x) = \frac{1}{2x^2+1} \cdot 2 \cdot 2x^{2-1}
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  3. Multiply:                                                                                                     f'(x) = \frac{4x}{2x^2+1}

<u>Step 3: Domain</u>

We know that we would have issues in the denominator when we have a rational expression. However, we can see that the denominator would never equal 0.

Therefore, our domain would be all real numbers.

We can also graph the differential function to analyze the domain.

5 0
3 years ago
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