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3 years ago

HELP ME PLEASE 10 POINTS ON IT PLEASE HELP ME

Mathematics

2 answers:

dimulka [17.4K]3 years ago

7 0

hope it helps

plz. mark as brainliest

nexus9112 [7]3 years ago

3 0

Answer:

45 adults, 30 boys, 105 girls

Step-by-step explanation:

Adults --- 3 units

Boys --- 2 units

Girls --- 7 units

Total

= 3 +2 +7

= 12 units

Since there are 180 people in total,

12 units --- 180 people

1 unit --- 180 ÷12= 15 people

Number of adults

= 3(15)

= 45

Number of boys

= 2(15)

= 30

Number of girls

= 7(15)

= 105

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1-3+30<br><br> Will give branliest to first answer

Mkey [24]

Answer:

Step-by-step explanation:

1 - 3 + 30

= -2 + 30

= 28

4 0

3 years ago

1- Tickets cost £18.50 to a music gig. The band sells 189 tickets and the

Elden [556K]

Answer:

The answer is £ 496

Profit ( P) = Selling price (S) - Cost price ( C)

From the above question

Cost price = £3000

To find the selling price multiply the price of one ticket by the number of tickets sold

That's

Selling price = £18.50 × 189 = £3496

So now

Profit = £3496 - £3000 = £ 496

Hope this helps you

5 0

4 years ago

In this card game, a player is dealt 10 cards. A player wins $1,000,000 if he is dealt 8 hearts. Use combinatorics to set up you

denis23 [38]

Assume a standard deck of 52 cards with 4 suits of 13 cards each.

a. There are $\dbinom{13}8\dbinom{39}2$ ways of being dealt a hand consisting of 8 hearts and 2 non-hearts, so the probability of being dealt such a hand is

$\dfrac{\dbinom{13}8\dbinom{39}2}{\dbinom{52}{10}}\approx0.0000602823$

b. This time, the non-hearts specifically belong to the suit of diamonds, for which there are $\dbinom{13}2$ ways of getting drawn, so the probability is

$\dfrac{\dbinom{13}8\dbinom{13}2}{\dbinom{52}{10}}\approx0.0000063455$

5 0

3 years ago

Round 84,978 to the nearest ten thousand

kvasek [131]

85,000 is the answer

6 0

4 years ago

Read 2 more answers

Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = 5y cos(z) i + ex sin(z) j + xey k, S is the hemisphere x2 + y2 + z2

Alenkinab [10]

By Stokes' theorem, the integral of the curl of $\vec F$ across $S$ is equal to the integral of $\vec F$ along the boundary of $S$ , call it $C$ . Parameterize $C$ by

$\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath$

with $0\le t\le2\pi$ . So we have

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_C\vec F\cdot\mathrm d\vec r$

$=\displaystyle\int_0^{2\pi}(10\sin t\cos 0\,\vec\imath+e^{2\cos t}\sin0\,\vec\jmath+2\cos t\,e^{2\sin t}\,\vec k)\cdot(-2\sin t\,\vec\imath+2\cos t\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^{2\pi}-20\sin^2t\,\mathrm dt$

$=\displaystyle-10\int_0^{2\pi}(1-\cos2t)\,\mathrm dt=\boxed{-20\pi}$

6 0

4 years ago

HELP ME PLEASE 10 POINTS ON IT PLEASE HELP ME ​

HELP ME PLEASE 10 POINTS ON IT PLEASE HELP ME