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Oksana_A [137]
3 years ago
7

Find the limit , picture provided

Mathematics
1 answer:
V125BC [204]3 years ago
7 0

Answer:

d. does not exist

Step-by-step explanation:

The given limits are;

\lim_{x \to 4} f(x) =5, \lim_{x \to 4} g(x) =0 and \lim_{x \to 4} h(x) =-2

We want to find

\lim_{x \to 4} \frac{f}{g}(x)= \lim_{x \to 4} \frac{f(x)}{g(x)}

By the properties of limits, we have;

\lim_{x \to 4} \frac{f}{g}(x)= \frac{\lim_{x \to 4} f(x)}{\lim_{x \to 4} g(x)}

This gives us;

\lim_{x \to 4} \frac{f}{g}(x)= \frac{5}{0}

Division by zero is not possible. Therefore the limit does not exist.

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Answer:

The value of <em> </em>\frac{14}{8} + \frac{15}{12}  = 3

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<u><em>Explanation</em></u>

<em>Given       </em>\frac{14}{8} + \frac{15}{12}<em></em>

<em></em>

<em>L.C.M     8 , 12   is  24</em>

<em>          </em>

<em>        </em>\frac{14}{8} + \frac{15}{12} = \frac{14 X 3 + 15 X 2}{24}<em></em>

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The value of <em> </em>\frac{14}{8} + \frac{15}{12}  = 3

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