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Oksana_A [137]
3 years ago
7

Find the limit , picture provided

Mathematics
1 answer:
V125BC [204]3 years ago
7 0

Answer:

d. does not exist

Step-by-step explanation:

The given limits are;

\lim_{x \to 4} f(x) =5, \lim_{x \to 4} g(x) =0 and \lim_{x \to 4} h(x) =-2

We want to find

\lim_{x \to 4} \frac{f}{g}(x)= \lim_{x \to 4} \frac{f(x)}{g(x)}

By the properties of limits, we have;

\lim_{x \to 4} \frac{f}{g}(x)= \frac{\lim_{x \to 4} f(x)}{\lim_{x \to 4} g(x)}

This gives us;

\lim_{x \to 4} \frac{f}{g}(x)= \frac{5}{0}

Division by zero is not possible. Therefore the limit does not exist.

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What is the ratio for sin Y if tan Y = 8/15?
jeyben [28]

Answer: 8/17

Step-by-step explanation: The ratio for tangent is opposite/adjacent. The side opposite from Y has a length of 8, and the side next to it has a length of 15. These are the lengths of the legs of the triangle. To find the sine ratio, you need the hypotenuse.

The hypotenuse can be found using the Pythagorean theorem. 8^2=64 and 15^2=225. 225+64=289. The square root of 289 is 17. The hypotenuse has a length of 17.

The ratio for sine is opposite/hypotenuse. Take the value of the opposite from the tangent ratio (8) and the length of the hypotenuse (17) to get 8/17.

6 0
3 years ago
What is the perimeter of a triangle with vertices of (5,1) (-3,3) (-7,-3)
timurjin [86]
Vertices:\\
A(5,1)\\B(-3,3)\\C(-7,-3)\\\\ You\ must\ find\ length\ of\ AB,\ BC,\ AC.\\\\
A(5,1)\ \ \ \ \ \ B(-3,3)\\\\Distance\ between\ A \ and\ B:\\AB=\sqrt{(x_B-x_A)^2+(y_A-y_B)^2}\\\\AB=\sqrt{(-3-5)^2+(3-1)^2}\\AB=\sqrt{8^2+2^2}\\AB=\sqrt{64+4}\\AB=\sqrt{68}

 B(-3,3)\ \ \ \ C(-7,-3)\\\\Distance\ between\ B \ and\ C:\\BC=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\\\BC=\sqrt{(-7-(-3))^2+(-3-3)^2}\\BC=\sqrt{(-4)^2+(-6)^2}\\BC=\sqrt{16+36}\\BC=\sqrt{52}A(5,1)\ \ \ \ \ \ C(-7,-3)\\\\Distance\ between\ A \ and\ C:\\AC=\sqrt{(x_C-x_A)^2+(y_C-y_A)^2}\\\\AC=\sqrt{(-7-5)^2+(-3-1)^2}\\AC=\sqrt{(-12)^2+(-4)^2}\\AC=\sqrt{144+16}\\AC=\sqrt{160}Perimeter\ of\ triangle=\ AB+AC+BC=\\\sqrt{68}+\sqrt{52}+\sqrt{160}=2\sqrt{17}+2\sqrt{13}+2\sqrt{40}
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3 years ago
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harkovskaia [24]
Y=2(151)+3

y=302+3

y=305

So the 151st term is 305
3 0
3 years ago
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Annette [7]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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murzikaleks [220]

Answer:

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